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miss Akunina [59]
4 years ago
6

Which sequence is geometric and has 1/4 as its fifth term and 1/2 as the common ratio?

Mathematics
2 answers:
olchik [2.2K]4 years ago
5 0
5th term = a1r^4   where a1 = first term and r = common ratio

so 1/4 = a1 * (1/2)^4

a1 = 1/4 / (1/2)^4  =  4

so the sequence  is  4 , 4*1/2, 4*(1/2)^2...

= 4, 2, 1, 1/2, 1/4 .....
wlad13 [49]4 years ago
3 0

Answer:

4, 2, 1, \frac{1}{2}.......

Step-by-step explanation:

Since explicit formula of a geometric sequence is represented by An = A_{1}(r)^{n-1}

It is given in the question that fifth term of the sequence is (\frac{1}{4}) and common ratio of the sequence is \frac{1}{2}.

Now from the explicit formula

A_{5}=\frac{1}{4} =A_{1}(\frac{1}{2})^{5-1}

\frac{1}{4}=A_{1}( \frac{1}{2})^{4}

A_{1} \frac{2^{4} }{4}

\frac{16}{4} = 4

Therefore, sequence will be 4, 4 × (\frac{1}{2}), 4 × \frac{1}{2}^{2}, 4 × (\frac{1}{2})³.........

= 4, 2, 1, \frac{1}{2}.......

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