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2 years ago

PLEASE HELP!!! 13 + 7 POINTS!!! THANK YOU!

Mathematics

1 answer:

grin007 [14]2 years ago

6 0

Answer:

7 inches

Step-by-step explanation:

Using Pythagoras' theorem on the right triangle, that is

r² + 11² = 13²

r² + 121 = 169 ( subtract 121 from both sides )

r² = 48 ( take the square root of both sides )

r = $\sqrt{48}$ ≈ 7 in ( to the nearest inch )

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Pls can someone help me and have it right

dangina [55]

Answer:

Problem 1:

a. x=2

b. x=3

c. x=1

Problem 2:

A multiplication equation to hold the table true:

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A division equation to hold the table true:

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Step-by-step explanation:

Given in problem 1:

(a). The equation is $\frac{x}{6} > 1$

It holds true for all values of $x> 6$ .

Let us say $x=12$ ,

$\frac{x}{6}=\frac{12}{6} =2$ which is greater than 1.

(b). The equation is $\frac{x}{6} < 1$

It holds true for all values of $x< 6$ .

Let us say $x=3$

$\frac{x}{6} =\frac{3}{6} =\frac{1}{2}$ which is less than 1.

(c). The equation is $\frac{x}{6} = 1$

It holds true for only $x= 6$ .

Let us say $x=6$ ,

$\frac{x}{6} =\frac{6}{6}=1$ which is equal to 1.

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Therefore these are the values which hold true to the equation in problem 1 and 2.

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Step-by-step explanation:

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What could the dimensions of a rectangle with an area of 48 inches be?

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3 x 16.

4 x 12.

6 x 8.

8 x 6.

12 x 4.

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2 years ago