Answer:
h(t)= 25 * sin (1 pi t + (-0.5) pi) + 29
Step-by-step explanation:
No Nothing Further Can Be Done
3.) 3sinθ = sinθ - 1
3sinθ - sinθ = -1
2sinθ = -1
sinθ = -1/2
θ = sin^-1(-1/2) = π + π/6, 2π - π/6 = 7π/6, 11π/6
4.) tan^2 θ = -3/2 sec θ
sin^2 θ / cos^2 θ = -3/2(1/cos θ)
sin^2 θ / cos θ = -3/2
1 - cos^2 θ = -3/2 cos θ
cos^2 θ - 3/2 cos θ - 1 = 0
2cos^2 θ - 3cos θ - 2 = 0
2cos^2 θ - 4cos θ + cos θ - 2 = 0
2cos θ (cos θ - 2) + 1(cos θ - 2) = 0
(2cos θ + 1) = 0 or (cos θ - 2) = 0
cos θ = -1/2 or cos θ = 2 [but cos θ can never be 2]
θ = cos^-1(-1/2) = π - π/3, π + π/3 = 2π/3, 4π/3
First, we could try to factorize the polynomial. We could group the first and third terms, and the second and fourth term:

Now, x(x^2-9) is a common factor:

.
By the difference of squares formula, our final factorization is :
x(3x-1)(x-3)(x+3).
Here we can see clearly that the roots of f(x) are 0, 1/3, 3, and -3.
Remark: we grouped the terms in pairs as we did, noticing that the ratio of the exponents, and coefficient in each pair was the same.
Answer: 0, 1/3, 3, and -3.
Answer:
Step-by-step explanation:
Question (1).
OQ and RT are the parallel lines and UN is a transversal intersecting these lines at two different points P and S.
A). ∠OPS ≅ ∠RSU [corresponding angles]
B). m∠OPS + m∠RSP = 180° [Consecutive interior angles]
C). m∠OPS + m∠OPN = 180° [Linear pair of angles]
D). Since, ∠OPS ≅ ∠TSP [Alternate interior angles]
And m∠TSP + m∠TSU = 180° [Linear pair of angles]
Therefore, Option (A) is the correct option.
Question (2).
A). m∠RSP + m∠RSU = 180° [Linear pair of angles]
B). m∠RSP + m∠PST = 180° [Linear pair of angles]
C). ∠RSP ≅ ∠TSU [Vertically opposite angles]
D). m∠RSP + m∠OPS = 180° [Consecutive interior angles]
Therefore, Option (C) will be the answer.