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4 years ago

What's the answer witch ones r composite 14 15 16 17 18 19 20 21

Mathematics

2 answers:

jenyasd209 [6]4 years ago

6 0

A composite number is a number with more than 2 factors and 16, 18, 20, and 21 are composite.

Serjik [45]4 years ago

4 0

14 and 15 are also composite:

14 - 1×14, 2×7
15 - 1×15, 3×5

the first person probably didn't see the first row of numbers

You might be interested in

The pulse rates of 174 randomly selected adult males vary from a low of 39 bpm to a high of 111 bpm. Find the minimum sample siz

Daniel [21]

Answer:

a. The sample size is approximately 97 adults

Step-by-step explanation:

The given parameters are;

The number of adults surveyed, n = 174

The lowest value of the pulse rate = 39 bpm

The highest value of the pulse rate = 111 bpm

The level of confidence used for determining the sample size = 90%

The given sample mean = 3 pm of the population mean

a. The range rule of thumb states that the standard deviation is approximately one quarter (1/4) of the range

The range = 111 bpm - 39 bpm = 72 bpm

Therefore, the standard deviation, σ = 72 bpm/4 = 18 bpm

The sample size, 'N', is given as follows;

$N = \dfrac{z^2 \cdot p \cdot q}{e^2}$

Where;

N = The sample size

z = The confidence level, 90% (z-score at 90% = 1.645)

p·q = σ² = 18² = 324

e² = 3² = 9

$N = \dfrac{1.645^2 \times 324}{3^2} = 97.4169$

Therefore the appropriate sample size, N ≈ 97 adults.

8 0

3 years ago

M AEB = 37°, what is m CED?

Oksana_A [137]

Answer: 53 degree

Explanation:

AEB + BEC + CED = 180 degree
37 + 90 + CED = 180
CED = 180 - 127
CED = 53 degree

6 0

3 years ago

(5+6b^3)^2 expand and combine like terms

Drupady [299]

Answer:

$( 5 + 6b^3)^2 = 36b^6 + 60b^3 + 25$

Step-by-step explanation:

$(a + b)^2 = a^2 + b^2 + 2ab$

So,

$(5 + 6b^3)^2 = (5)^2 + (6b^3)^2 + 2 (5)(6b^3)$

$= 25 + 36b^6 + 60b^3$

7 0

3 years ago

One of our brainliest, Konrad509, made this:

Reil [10]

$\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x$

A=10, B=11, C=12, etc.

$\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2$

$121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0$

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that $x\in\mathbb{N}$ . Moreover we can deduce that $x\geq19$ since there is $J$ and $J=19$ .

After you succesfully solve it, you should get the answer $x=20$ .

7 0

4 years ago

Help meh please <br><br> -2/3 ÷ (-15)

pogonyaev

The answer is 0.04444... or 2/45. Whichever is more useful to you.

3 0

3 years ago

Read 2 more answers