Ask question

Ask question

All categories

3 years ago

9

At the market you can buy 5 bags of apples for $23.60. At the orchard you can get 7 bags of apples for $32.76. Which is the bett

er deal?

1 answer:

lisabon 2012 [21]3 years ago

3 0

the orchard

Step-by-step explanation:

because at the market it is $4.72 per bag and at the orchard they are $4.68 per bag and $4.72>$4.68

You might be interested in

A cheetah can run 60 miles per hour. A lion can

mafiozo [28]

Answer:

Step-by-step explanation:

cheetah runs 60 miles/hour

lion runs 50 miles/hour

answer A

5 0

3 years ago

Read 2 more answers

A composite figure is shown.

VikaD [51]

The surface area of the pyramid is 60 square feet

The surface area of the square prism is 480 square feet

The surface area of the cube is 180 square feet

The total surface area is 720 square feet

<h3>Area of Composite figures</h3>

From the question, we are to calculate the surface area of each part of the composite figure

For the cube

Surface area of a cube is given by

$S = 6l^{2}$

Where $l$ is the length of a side

But only have 5 surfaces of the cube are part of the composite figure

∴ Surface area of the cubic part of the figure = $5l^{2}$

From the given information,

$l = 6 \ feet$

∴ Surface area of the cubic part of the figure = 5 × 6²

Surface area of the cubic part of the figure= 180 square feet

For the square prism

The surface area of a square prism is given by the formula,

$S = 2l^{2} + 4lh$

Where $l$ is the length of the sides and

$h$ is the height

But the <u>square surfaces</u> are not part of the surface of the figure

∴ Surface area of the square prism in the figure = $2l^{2} + 4lh - 2l^{2}$

Surface area of the square prism in the figure = $4lh$

From the given information,

$l = 6 \ feet$

$h = 20 \ feet$

Thus,

Surface area of the square prism part of the figure = 4×6×20

Surface area of the square prism part of the figure = 480 square feet

For the pyramid

The pyramid is a square pyramid

The surface area of a square pyramid is given by

$S = l^{2} + 2l\sqrt{\frac{l^{2} }{4}+h ^{2} }$

Where $l$ is the base length

and $h$ is the height of the prism

But the <u>square base</u> is not part of the surface of the figure

∴ Surface area of the pyramid part of the figure = $l^{2} + 2l\sqrt{\frac{l^{2} }{4}+h^{2} }\ - ( l^{2})$

Surface area of the pyramid part of the figure = $2l\sqrt{\frac{l^{2} }{4}+h^{2} }$

From the given information,

$l = 6 \ feet$

$h = 4 \ feet$

∴ Surface area of the pyramid part of the figure = $2(6)\sqrt{\frac{6^{2} }{4}+4^{2} }$

= $12\sqrt{\frac{36 }{4}+16}$

= $12\sqrt{9+16 }$

= $12\sqrt{25}$

= 12 × 5

= 60 square feet

Hence, the surface area of the pyramid is 60 square feet

Thus,

The total surface area = 180 square feet + 480 square feet + 60 square feet

The total surface area = 720 square feet

Hence, the total surface area is 720 square feet

Learn more on Calculating area of composite figures here: brainly.com/question/13175744

#SPJ1

4 0

2 years ago

Complete the table shown below. f(x) = 2x2 - 8x + 6 1 0 2 y 3 4. 6 X= y = Z

Serga [27]

Answer:

x = 6, y = -2, z = 0

Step-by-step explanation:

To find x, we have to plug 0 into f(x). Therefore, x = f(0) = 2 * 0² - 8 * 0 + 6 = 6. Similarly, to find y, we have to plug 2 into f(x) so y = f(2) = 2 * 2² - 8 * 2 + 6 = -2. Finally, z = f(3) = 2 * 3² - 8 * 3 + 6 = 0.

4 0

3 years ago

Pls help meh pls<br> Find the area of the figure. (Sides meet at right angles.)

Vlad [161]

We find the area of the total square which is 8in • 8in=64in^2 . Now we find the area of the small quadrilateral which is 4in•4in=16 in^2.
Now we subtract the area of the small quadrilateral from the big quadrilateral’s area 64in^2 -16in^2 leaving us with the are of 48in^2 of the figure

3 0

3 years ago

100 POINTS!! PLEASE HELP IM REALLY CONFUSED

11111nata11111 [884]

Answer:

1:

<A=½(arcJL)=½(70+120)=35+60=95°

[inscribed angle is half of central angle]

2:

<W=½arcVX=½(130)=65°

[inscribed angle is half of central angle]

3.

<E=½(arcDC)=½(90)=45°

[inscribed angle is half of central angle]

4.

<R=½(arcXZ)=½(110+62)=86°

[inscribed angle is half of central angle]

5.

<B=½(arc DC)=½×104°=52°

[inscribed angle is half of central angle]

6.

<K=90°

[inscribed angle in a diameter is complementary]

<K+<J+<L=180°(sum of interior angle of a triangle]

<L=180°-90°-53°=37°

again

arc JK=2×<L=2×37=74°

3 0

3 years ago