The point Q on a line segment with end points(2,1) and (4,2) is Q(12/5, -2/5)
<h3>What is a line segment?</h3>A line segment is a straight line that passes through two given points.
The end points of the line determine how long or short a given line segment would be.
Analysis:
point Q(x, y )
x =
y =
where M :N = 4:1
x1 = 2, x2 = 4, y1 = -1, y2 = 2
x = = 12/5
y = = -2/5
In conclusion, the point Q is (12/5, -2/5).
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x² - x - 12 ≠ 0
x² - 4x + 3x - 12 ≠ 0
x (x - 4) + 3 (x - 4) ≠ 0
(x + 3)(x - 4) ≠ 0
x ≠ -3 or x ≠ 4
(B)
Answer:
There are no solutions for the pair of equations.
The lines are parallel to each other
Step-by-step explanation:
Line Q has a slope of 1/2 and crosses the y axis at 3.
This mean at x=0, y=3
Using the equation of a straight line expression to find the slope
y=mx +c where m is slope and c in the y intercept you can write the equation for Line Q as;
For the Line S , slope is 1/2 and the line crosses the y axis at -2 , which represents the c in the equation y=mx +c
The equation for S will be
Using the graphing tool to plot the two equations for line Q and line S we notice that the lines are parallel .For solutions, they have to intersect.
