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VladimirAG [237]

3 years ago

5

A company mixes two kinds of cleansers to get a blend they sell for 59 cents a liter. One of the cleansers costs 50 cents per li

ter, and the other 80 cents per liter. How much of each kind should be mixed to get 2,000 liters of the blend?

1 answer:

Svetllana [295]3 years ago

5 0

Answer:

I actually don't know I am comfused

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What is (16, -6) dilated with a scale factor of 1.5

Alexandra [31]

We need to see the other points

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3 years ago

Plsss Help me plsssssssssssss

Mazyrski [523]

Answer:

If, a = 2 and b = 3

<h3>Jada</h3><h3> $10a + 1b = 7a + 5b - 3a + 4b \\ 10(2) + 1(3) = 7(2) + 5(3) - 3(2) + 4(3) \\ 20 + 3 = 14 + 15 - 6 + 12 \\ 23 = 35 \\$ </h3>

It's not equivalent.

<h3>Diego</h3><h3> $4a + 9b = 7a + 5b - 3a + 4b \\ 4(2) + 9(3) = 7(2) + 5(3) - 3(2) + 4(3) \\ 8 + 27 = 14 + 15 - 6 + 12 \\ 35 = 35 \\$ </h3>

It's equivalent.

The correct equation is 4a + 9b.

5 0

2 years ago

A youth group is setting up camp. Rain is predicted, so the campers decide to build a fly, or rain cover, over their tent. The f

pshichka [43]

The image for this is attached for reference. This problem can be used by the Pythagorean equation. To make solving convenient, let us see only one part of the tent. Hence, one side is half of the tend width which is 16/2ft. Height is 12 ft. The unknown side is the hypotenuse. The answer is:
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3 years ago

F(x) = 10x2 + 8, evaluate f(-3).

OlgaM077 [116]

Answer:

98

Step-by-step explanation:

f(x) = 10x² + 8

= 10(-3)² + 8

= 10 (9) + 8

= 90 + 8

= 98

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3 years ago

Assume that the Poisson distribution applies and that the mean number of aircraft accidents is 9 per month. Find P(0), the prob

Ugo [173]

Answer: 0.0001

It is unlikely to have a month with no aircraft accidents .

Step-by-step explanation:

Given : Mean number of aircraft accidents = 9 per month

The Poisson distribution formula :-

$\dfrac{e^{-\lambda}\lambda^x}{x!}$ , where $\lambda$ is the mean of the distribution.

If X = the number of aircraft accidents per month, then the probability that in a month, there will be no aircraft accidents will be :-

$\dfrac{e^{-9}(9)^0}{0!}=0.000123409804087\approx0.0001$

Hence, the probability that in a month, there will be no aircraft accidents = 0.0001

Since this is less than 0.5 , therefor it is unlikely to have a month with no aircraft accidents .

5 0

3 years ago