All categories

3 years ago

Find the missing term.

Mathematics

2 answers:

Inessa [10]3 years ago

6 0

Answer:

x^158

Step-by-step explanation:

x^12^5 is x^60

x^-2^9 is x^-18

x^60*x^-18 = x^60-18=x^42

x^40^5 is x^200

x^42 *x^y=x^200

200-42 is 158

y=158.

The blank is x^158.

Hope this helps plz hit the crown :D

fomenos3 years ago

4 0

Answer:

$x^{158}$ yes to the 158 :/ I don't know any thing that would need that big of a number :|

Step-by-step explanation:

You might be interested in

Maria started a bank account in March. The amount of money that she had in April was $4600. The amount of money she had is May w

Studentka2010 [4]

X3+5175+4600+5125=y will be your equation

6 0

3 years ago

A cylindrical container of five rubber balls has a height of 30 centimeters and a diameter of 6 centimeters. Each ball in the co

Artyom0805 [142]

Answer:

There is 170 cm³ free space in the container.

Step-by-step explanation:

Cylindrical container: height = 18 cm ; diameter = 6 cm.

3 balls each have a radius of 3 cm.

Volume of a cylinder = π r² h

V = 3.14 * (3cm)² * 18 cm

V = 508.68 cm³

Volume of rubber ball = 4/3 π r³

V = 4/3 * 3.14 * (3cm)³

V = 113.04 cm³

113.04 cm³ * 3 balls = 339.12 cm³

508.68 cm³ - 339.12 cm³ = 169.56 cm³ or 170 cm³

3 0

3 years ago

Write the given trinomial if possible as a square of a binomial or as an expression opposite to a square of a binomial: 15ab-9a^

MrMuchimi

Answer:

$- \bigg(3a - \frac{5}{2} b) \bigg)^{2}$

Step-by-step explanation:

$15ab-9a^2-6 \frac{1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{6 \times 4 + 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{24+ 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{25}{4} b^2 \\ \\ = 15ab- (3a)^2- \bigg(\frac{5}{2} b \bigg)^2 \\ \\ = - \{ - 15ab + (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 \} \\ \\ = - \{ (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 - 15ab \} \\ \\ = - \bigg(3a - \frac{5}{2} b \bigg)^{2}$

3 0

3 years ago

Find mZ3 if mZ5 = 145º and mZ4 = 45°

trapecia [35]

9514 1404 393

Answer:

C. 100°

Step-by-step explanation:

The exterior angle is equal to the sum of the remote interior angles.

∠5 = ∠3 +∠4

145° = ∠3 +45° . . . . fill in the given values

100° = ∠3 . . . . . . subtract 45° from both sides

7 0

3 years ago

A triangle has two sides of length 15 cm and 17 cm. Select all the values of its third side that would make it a right triangle

Natali [406]

Answer:

$\sqrt{514} cm$ , 8cm, are both options

Step-by-step explanation:

For a right triangle one can find the length of the longest side by using the Pythagorean theorem. So there are two options I can think of that if the triangle is a right triangle will work. First remember what the Pythagorean theorem is : side a^2+side b^2=hypotenuse^2

The hypotenuse is the longest side of a right triangle. So if the sides that are 15 and 17 cm are not the longest sides then the formula would be:

$15^{2} +17^2=c^2\\15^2+17^2=\sqrt{514}cm$

But if 17cm is the longest side then:

$a^2+15^2=17^2\\8^2+15^2=17^2\\a=8cm$

Hope this helps!

4 0

3 years ago

Read 2 more answers