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enyata [817]
4 years ago
8

Match each molecular formula to the corresponding empirical formula.

Chemistry
1 answer:
sp2606 [1]4 years ago
8 0

The given question is incomplete. The complete question is:

Match each molecular formula to the corresponding empirical formula.

A.) C_4H_8O_2

B.) C_4H_{12}O_4

C.) C_2H_{10}O_2

1.) CH_3O

2.) CH_5O

3.) C_2H_4O

Answer: C_4H_8O_2: C_2H_4O

C_4H_{12}O_4: CH_3O

C_2H_{10}O_2: CH_5O

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

A) Thus the simplest whole number ratio of atoms for C_4H_8O_2 is C_2H_4O

B) Thus the simplest whole number ratio of atoms for is C_4H_{12}O_4 is CH_3O

C) Thus the simplest whole number ratio of atoms for isC_2H_{10}O_2 is CH_5O

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Chromium is dissolved in sulfuric acid according to the following equation: Cr + H2SO4 ⇒ Cr2 (SO4) 3 + H2
Usimov [2.4K]

Answer:

\large \boxed{\text{a)188.4 g; b) 98.67 $\, \%$}}

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:                      98.08           392.18

             2Cr + 3H₂SO₄ ⟶ Cr₂(SO₄)₃ + 3H₂

To solve the stoichiometry problem, you must

  • Use the molar mass of H₂SO₄ to convert  the mass of H₂SO₄ to moles of H₂SO₄
  • Use the molar ratio to convert moles of H₂SO₄ to moles of Cr₂(SO₄)₃
  • Use the molar mass of Cr₂(SO₄)₃ to convert moles of Cr₂(SO₄)₃ to mass of Cr₂(SO₄)₃

a) Mass of Cr₂(SO₄)₃

(i) Mass of pure H₂SO₄

\text{Mass of pure} = \text{165 g impure} \times \dfrac{\text{85.67 g pure} }{\text{100 g impure}} = \text{141.36 g pure}

(ii) Moles of H₂SO₄

\text{Moles of H$_{2}$SO}_{4} = \text{141.36 g H$_{2}$SO}_{4} \times \dfrac{\text{1 mol H$_{2}$SO}_{4}}{\text{98.08 g H$_{2}$SO}_{4}} = \text{1.441 mol H$_{2}$SO}_{4}

(iii) Moles of Cr₂(SO₄)₃

The molar ratio is 1 mol Cr₂(SO₄)₃:3 mol H₂SO₄ \text{Moles of Cr$_{2}$(SO$_{4}$)}_{3} = \text{1.441 mol H$_{2}$SO}_{4} \times \dfrac{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}}{\text{3 mol H$_{2}$SO}_{4}} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3}

(iv) Mass of Cr₂(SO₄)₃ \text{Mass of Cr$_{2}$(SO$_{4}$)}_{3} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3} \times \dfrac{\text{392.18 g Cr$_{2}$(SO$_{4}$)}_{3}}{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}} = \textbf{188.4 g Cr$_{2}$(SO$_{4}$)}_{3}\\\text{The mass of Cr$_{2}$(SO$_{4}$)$_{3}$ formed is $\large \boxed{\textbf{188.4 g}}$}

b) Percentage yield

It is impossible to get a yield of 485.9 g. I will assume you meant 185.9 g.

\text{Percentage yield} = \dfrac{\text{Actual yield}}{\text{Theoretical yield}} \times 100 \, \% = \dfrac{\text{185.9 g}}{\text{188.4 g}} \times 100 \, \% = \mathbf{98.67 \, \%}\\\\\text{The percentage yield is $\large \boxed{\mathbf{98.67 \, \%}}$}

7 0
4 years ago
For the following gases, correct the volumes to the conditions indicated. A.654 cm3 at 6 degrees Celsius and 65.3 kPa to 4 degre
leva [86]

Initial pressure of the gas = 65.3 kPa  

Initial volume of the gas = 654 cm³

Initial temperature of the gas = 6⁰C = 273 + 6 = 279 K

Final pressure of the gas = 108.7 kPa

Final temperature of the gas = 4⁰C = 273 + 4 = 277 K

Using the combined gas law for ideal gases:

P₁V₁/T₁ = P₂V₂/T₂  

where P₁, V₁ and T₁ are the pressure, volume and temperature for the initial state and P₂, V₂ and T₂ are the pressure, volume and temperature for the final state.

Plugging the given data into the combined gas law we have,

(65.3 kPa x 654 cm³) / (279 K) = (108.7 kPa x V₂)/(277 K)

V₂ = (65.3 kPa x 654 cm³ x 277 K) / (279 K x 108.7 kPa)

V₂ = 390.1 cm³


8 0
3 years ago
2. Calculating density of an object with a regular shape
Tatiana [17]

D= 0.10125kg/m^3

EXPLAINATION
Density =mass/volume
D= 226.8/20 x 8 x 14
D=226.8/2240
D= 0.10125kg/m^3
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Vikki [24]

Answer:

A

Explanation:

Conducts electricity:

-Steel

-Gold

-Copper

-Aluminum

Does not conduct electricity:

-Plastic

-Glass

-Rubber

-Wood

Metallic bonding causes metals to conduct electricity. Some metals are more highly conductive than others.

Hope this helps :)

5 0
3 years ago
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After reading “The Crisis, No. 1,” what do you think Paine means by the line, "These are the times that try men’s souls"? Cite e
posledela
Paine is referring to the difficulties facing the colonists to stand up against the British Empire against imposed taxes and foreign rule. He says "<span>Tyranny, like hell, is not easily conquered; yet we have this consolation with us, that the harder the conflict, the more glorious the triumph". This emphasises his point that the fight is against tyranny, although the battle may be difficult.</span>
3 0
3 years ago
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