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andrew-mc [135]
2 years ago
13

How many grams of aluminum will be deposited by 0.1F? (Al=27) a.0.3g b. 0.9. c. 9.0g. d. 2.7g​

Chemistry
1 answer:
andrezito [222]2 years ago
5 0

Based on the charge on the aluminium ion, 0.9 g of aluminium are deposited by 0.1 F of electricity.

<h3>What is electrolysis?</h3>

Electrolysis is the decomposition of a substance known as an electrolyte when electric current is passed through it.

The mass and hence moles an electrolyte deposited when current is passed through it depends on the charge on the ion.

Aluminium ion has a charge of +3 and requires 3F of electricity to deposit 1 mole or 27 g of aluminium

0.1 F will discharge = 0.1/3 × 27 g of aluminium

mass of aluminium deposited = 0.9 g of aluminium.

Therefore, 0.9 g of aluminium are deposited by 0.1 F of electricity.

Learn more about electrolysis at: brainly.com/question/26050361

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Compound A, C6H12 reacts with HBr/ROOR to give compound B, C6H13Br. Compound C, C6H14, reacts with bromine and light to produce
Savatey [412]

Answer:

The question involves drawing of structures and showing mechanism in which brainly text editor did not support. I made sure I created a pdf file with both the anwsers and explanations in it. The pdf can be found in the attachment below.  

Explanation:

Download pdf
3 0
3 years ago
What is the overall charge of an atom with 18 protons, 18 neutrons, and 19 electrons?
Charra [1.4K]

Answer:

as no. of protons is equals to the no. of electrons so, it is a neutral atom.

but, as Atomic No. = Mass No. - No. of neutrons

Atomic No. = No. of protons = 18

so, Mass No. = Atomic No. + No. of Neutrons= 18 + 20 = 38

so, correct option is C.

Explanation:

8 0
3 years ago
Urgent!!!
Yakvenalex [24]

The specific heat of the metal, given the data from the question is 0.60 J/gºC

<h3>Data obtained from the question </h3>

The following data were obtained from the question:

  • Mass of metal (M) = 74 g
  • Temperature of metal (T) = 94 °C
  • Mass of water (Mᵥᵥ) = 120 g
  • Temperature of water (Tᵥᵥ) = 26.5 °C
  • Equilibrium temperature (Tₑ) = 32 °C
  • Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
  • Specific heat capacity of metal (C) =?

<h3>How to determine the specific heat capacity of the metal</h3>

The specific heat capacity of the sample of gold can be obtained as follow:

According to the law of conservation of energy, we have:

Heat loss = Heat gain

MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)

74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)

C × 4588 = 2761.44

Divide both side by 4588

C = 2761.44 / 4588

C = 0.60 J/gºC

Thus, the specific heat capacity of the metal is 0.60 J/gºC

Learn more about heat transfer:

brainly.com/question/6363778

#SPJ1

6 0
1 year ago
Which group on the Periodic Table reacts violently with water by igniting hydrogen gas?
Artemon [7]

Answer:

the answer would be Halogens

4 0
3 years ago
Four of the following pairs of acids list the weaker acid at the left and the stronger acid at the right. Which pair is reversed
atroni [7]

Answer:

d. pair

Explanation:

because,H3PO4 is a strong acid

6 0
3 years ago
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