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3 years ago

Please Help me with this problem

Chemistry

2 answers:

ivolga24 [154]3 years ago

5 0

The lava is melted rock from within the earth. When the volcano erupts, it spews the lava outward. Later, the magma cools, forming hard rock on the surface.

Alex73 [517]3 years ago

5 0

The rocks are breaking down and forming together as the lava soften stone they bind together

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An experiment shows that a 250 ?ml gas sample has a mass of 0.430 g at a pressure of 736 mmhg and a temperature of 28 ?c.

dmitriy555 [2]

What we're looking for here is the gas sample's molar mass given its mass, pressure, volume, and temperature. Recalling the gas law, we have

$PV = nRT$ or
$n = \frac{PV}{RT}$

where R is <span>0.08206 L atm / mol K, P is the given pressure, T is the temperature, and V is the volume.

Before applying the values given, it is important to make sure that they are to be converted to have consistent units with that of R.
</span>
Thus, we have

P = 736/ 729 = 0.968 atm
T = 28 + 273.15 = 301.15 K
V = 250/1000 = 0.250 L

Now, applying these converted values into the gas law, we have

$n = \frac{(0.968 atm)(0.250 L)}{(0.08206 L.atm/mol.K)(301.15 K)}$
$n = 0.00979 moles$

Given that the mass of the sample is 0.430 g, we have

$molar mass = \frac{mass}{number of moles}$
$molar mass = \frac{0.430}{0.00979} = 43.9$

Thus, the gas sample has a molar mass of 43.9 g/mol.

4 0

3 years ago

Four nails have a total mass of 4.42 grams how many moles of iron atoms do they contain

deff fn [24]

Answer:4.42 g= 1 mol/55.845 =.079 moles of Fe

Explanation:Given 4.42 grams of Fe. The atomic weight of Fe(iron) found on the periodic table is 55.845. Divide grams by the atomic weight to convert to moles.

5 0

3 years ago

When the pressure and number of particles are kept constant for a sample of gas, which of the following is also constant for the

Leno4ka [110]

The answer is D....................

7 0

3 years ago

in a certain solvent is first order with respect to (CH3)3CBr and zero order with respect to OH2. In several experiments the rat

Inga [223]

Answer:

Ea= -175.45J

A= 3.5×10^14

k=3.64 ×10^14 s^2.

Explanation:

From

ln k= -(Ea/R) (1/T) + ln A

This is similar to the equation of a straight line:

y= mx + c

Where m= -(Ea/R)

c= ln A

y= ln k

Therefore

21.10 3 104= -(Ea/8.314)

Ea=-( 21.10 3 104×8.314)

Ea= -175.45J

b) ln A= 33.5

A= e^33.5

A= 3.5×10^14

k= Ae^-Ea/RT

k= 3.5×10^14 × e^ -(-175.45/8.314×531)

k = 3.64 ×10^14 s^2.

8 0

3 years ago

A 2.950×10−2 M solution of glycerol (C3H8O3) in water is at 20.0∘C. The sample was created by dissolving a sample of C3H8O3 in w

11111nata11111 [884]

Answer:

The molality of the glycerol solution is 2.960×10^-2 mol/kg

Explanation:

Number of moles of glycerol = Molarity × volume of solution = 2.950×10^-2 M × 1 L = 2.950×10^-2 moles

Mass of water = density × volume = 0.9982 g/mL × 998.7 mL = 996.90 g = 996.90/1000 = 0.9969 kg

Molality = number of moles of glycerol/mass of water in kg = 2.950×10^-2/0.9969 = 2.960×10^-2 mol/kg

7 0

3 years ago