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RoseWind [281]
2 years ago
5

Science 5th grade very PLZ answer correctly TYSM WILL MARK AS BRAINLIST IF ANSWERED TODAY!

Chemistry
2 answers:
Charra [1.4K]2 years ago
8 0

Answer:

The first table correctly classifies the materials.

Explanation:

In table 1, all the elements on the left side are transition metals, expect for steel. Steel is not an element, it's an alloy (Which is a combination of two or more elements).Transition metals are very good conductors of heat and electricity. The reason why transition metals make such good conductors is because their outer electrons can move freely in their atom.

The right side of table 1 correctly classifies the materials that do not conduct electricity. The reason why those materials are poor conductors is because they all have their electrons tightly bound to their atoms.

In table 2, it classifies copper has a poor conductor which is wrong. It also classifies wood as a good conductor which also wrong for the reasons I stated above.

Vikki [24]2 years ago
5 0

Answer:

A

Explanation:

Conducts electricity:

-Steel

-Gold

-Copper

-Aluminum

Does not conduct electricity:

-Plastic

-Glass

-Rubber

-Wood

Metallic bonding causes metals to conduct electricity. Some metals are more highly conductive than others.

Hope this helps :)

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Answer:

Option C. 13.5 atm

Explanation:

From the question given above, the following data were obtained:

Pressure of Neon (Pₙₑ) = 4.1 atm

Pressure of Argon (Pₐᵣ) = 3.2 atm

Pressure of nitrogen (Pₙ₂) = 6.2 atm

Total pressure (Pₜ) =?

The total pressure in the container can be obtained by adding the pressure of the individual gases. This is illustrated below:

Pₜ = Pₙₑ + Pₐᵣ + Pₙ₂

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Explanation:

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Given the following data: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39
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Answer:

ΔH° = -11 kj

Explanation:

Step 1: Data given

1)   Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g)    ΔH = −23 kJ

2)   3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g)   ΔH = −39 kJ

3)   Fe3O4(s) + CO(g) → 3 FeO(s) + CO2(g) ΔH = +18 kJ

Step 2: The balanced equation

FeO + CO → Fe + CO2

Step 3:  Calculate ΔH for the reaction FeO(s) + CO(g) → Fe(s) + CO2(g).

To get this equation, we need to combine the 3 equations

We have to multiply the third equation by 2.

2Fe3O4(s) + 2CO(g) → 6 FeO(s) + 2CO2(g) ΔH = +54 kJ

<u>This equation we add to the second equation</u>

3Fe2O3(s) + CO(g) + 2Fe3O4(s) + 2CO(g) → 2Fe3O4(s) + CO2(g) + 6FeO(s) + 2CO2 (g)

3Fe2O3(s) + 3CO(g) →  3CO2(g) + 6FeO(s)

ΔH°  = 2*18 + (-39) = 36 - 39 =  -3 kJ

<u>This new equation we will divide by 3 </u>

3Fe2O3(s) + 3CO(g) →  3CO2(g) + 6FeO(s)

Fe2O3(s) + CO(g) →  CO2(g) + 2FeO(s)

ΔH°  =-3/3 = -1 kJ

<u>Now we will substract this new equation from the first equation</u>

Fe2O3(s) + 3CO(g) - Fe2O3(s) - CO(g) → 2Fe(s) + 3CO2(g) -2FeO(s) - CO2(g)

2CO(g)  + 2FeO(s)  → 2Fe(s) + 2CO2(g)

ΔH° = -23kJ +1kJ

ΔH° = -22 kj

<u>The next equation we will divide by 2</u>

2CO(g)  + 2FeO(s)  → 2Fe(s) + 2CO2(g)

CO(g)  + FeO(s)  → Fe(s) + CO2(g)

ΔH° = -22kJ /2

ΔH° = -11 kj

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