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OleMash [197]
3 years ago
12

Let x= the length of

Mathematics
1 answer:
Natali [406]3 years ago
8 0

Answer:

y

Step-by-step explanation:

y is smaller because

1 millimeter = 0.001m

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Suppose a triangle has sides a, b, and c, and the angle opposite the side of length b is obtuse. What must be true?
anyanavicka [17]

Answer: D.a^2 + b^2 < c^2

Step-by-step explanation:

In the given figure, we have an obtuse triangle which has sides a, b, and c, and the angle opposite the side of length b is obtuse.

∵ In a triangle, the side opposite to the largest angle is largest.

Thus, the largest side in then given obtuse triangle= c

The Pythagorean inequalities theorem says that If a triangle is obtuse than the square of the largest side is greater than the sum of square of other two sides.

Therefore, we have

a^2 + b^2 < c^2

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3 years ago
Unit 10 | Lesson 5 Lesson Checkpoint: Show What You Know Question Navigator Choose the answer. 2. (1 pt) Which answer is the mos
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The answer is B.about 400, because if you multiply 18 by 24 you get the answer without rounding, and that answer would be 434; once 434 is rounded to the closest possible answer, you get that the answer, which is, as stated before, B. about 400.
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4 years ago
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

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2 years ago
Write a function rule for the table.
Pavlova-9 [17]
The correct answer is:  [C]:  " p = 6.25 h " .
______________________________________________________
Explanation:  
______________________________________________________

It is clear that "pay" is a function of "hours worked" ; 

So, we can eliminate:  "Choice [B]:  " h = <span>6.25p" .
______________________________________________________
Try, Choice [A]:  " </span>p = h + 12.5 " ; and 14.50 ≠ 12.50 ; (12.50 is the amount shown in the table.  So, we can already eliminate "Choice [A]".
<span>_____________________________________________
Now that we have eliminated choices [A] and [B]; 

we are left with choices:  [C] and [D]:
_____________________________________________
Consider choice [C]:  " </span><span>p = 6.25h " ;  
</span>   when "h = 2" ; does: "p = 12.5" (as shown on table)?? ; 

i.e. " 12.5 =? 6.25 * (2) ?? Yes!  This choice is a POSSIBILITY.
_____________________________________________
Consider choice [D]:  " p = 12.5h" .

When "h = 2, does "p = 12.5" (as shown on table)?  No!  
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the value of "p" is DOUBLE [that of "12.5"].
 ________________________________________________
The correct answer is:  Answer choice:  [C]:   " <span>p = 6.25 h " .
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Answer:

1/12

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3 years ago
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