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drek231 [11]
4 years ago
9

In order to solve for the variable in the equation 2 (x + 3) + 5 x = 3 (2 x minus 1), Jaleesa begins by applying the distributiv

e property, then combines like terms. Which equation is the result of these steps? 7 x + 6 = 6 x minus 3 2 x + 6 + 5 x = 6 x minus 3 2 x + 3 + 5 x = 6 x minus 1 7 x + 3 = 6 x minus 1
Mathematics
2 answers:
larisa [96]4 years ago
6 0

Answer:

The answer is A

Step-by-step explanation:

I did the quiz and got it right. Also, its the only one that makes sense!!

;) Duhh....

Delvig [45]4 years ago
4 0

Answer:

7x + 6 = 6x - 3

Step-by-step explanation:

2(x+3) + 5x = 3(2x-1)

Distribute

2x + 6 + 5x = 6x - 3

Combine like terms

7x + 6 = 6x - 3

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An investment strategy has an expected return of 15 percent and a standard deviation of 9 percent. Assume investment returns are
IgorLugansk [536]

Answer:

68% of an investment earning a return between 6 percent and 24 percent.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 15

Standard deviation = 9

How likely is it to earn a return between 6 percent and 24 percent?

6 = 15 - 1*9

6 is one standard deviation below the mean

24 = 15 + 1*9

24 is one standard deviation above the mean

By the empirical rule, there is a 68% of an investment earning a return between 6 percent and 24 percent.

6 0
3 years ago
PLEASE HELP ME YALL i’m not bout to fail this test bruh
soldier1979 [14.2K]
Rhchridjdjxj j ndjdjdjdn no jdjd
5 0
3 years ago
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Help please........... ​
telo118 [61]

Answer:

18

Step-by-step explanation:

3 x 6=18

5 0
3 years ago
A scientist claims that 4% of viruses are airborne. If the scientist is accurate, what is the probability that the proportion of
oksano4ka [1.4K]

Answer:

The probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%=0.00427

Step-by-step explanation:

We are given that

\mu_{\hat{p}}=p=4%=0.04

n=662

We have to find the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%.

q=1-p=1-0.04=0.96

\sigma_{\hat{p}}=\sqrt{p(1-p)/n}

\sigma_{\hat{p}}=\sqrt{\frac{0.04(1-0.04)}{662}}

\sigma_{\hat{p}}=0.0076

Now,

P(\hat{p}>0.06)=1-P(\hat{p}

=1-P(\frac{\hat{p}-\mu_{\hat{p}}}{\sigma_{\hat{p}}}

=1-P(Z

=1-0.99573

P(\hat{p}>0.06)=0.00427

Hence, the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%=0.00427

7 0
3 years ago
Oliver and Marie are graphing two equations on a coordinate grid. Oliver has graphed the equation y = 2x + 2. If Marie graphs y
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It will be 5 down from Olivier's graph at -3 (Oliver's is at 2)
8 0
4 years ago
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