Question

What is the equation, in slope-intercept form, of the line that passes through (0, 6) and has a slope of 4? y = 4x − 6 y = 4x + 6 y = 6x − 4 y = 6x + 4

Answer 1

Option B is correct.

ANSWER:  

The equation in slope-intercept form, of the line that passes through (0, 6) and has a slope of 4 is y = 4x + 6

SOLUTION:  

Given, Point P (0, 6) and slope = 4

We need to find the equation in Slope-intercept form.  

The slope intercept form is given as y = mx + c    -------- eqn (1)

Where, m is the slope of line  

C is intercept made on x-axis by the line.

We have a point and the slope, so first we can find equation using point-slope form and then convert into slope-intercept form.

Now, point-slope form is given as $y-y_{1}=m\left(x-x_{1}\right)$ --- eqn 2

Put $\mathrm{x}_{1}=0 \text { and } \mathrm{y}_{1}=6$ in eqn (2) along with m = 4

$y-y_{2}=m\left(x-x_{1}\right)=y-6=4(x-0)$

y – 6 = 4x  

We got the equation in point slope form, now let’s convert it into slope intercept form.

y – 6 = 4x  

y = 4x + 6

Here, slope (m) = 4 and intercept (c) = 6

Hence we can conclude that, equation, in slope-intercept form, of the line that passes through (0, 6) and has a slope of 4 is y = 4x + 6

Answer 2

Answer:

y = 4x + 6

Step-by-step explanation:

y=mx+b

m= slope

b = y intercept