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3 years ago

12 people are entered in a race. if there are no ties, in how many ways can the first three places come out.

Mathematics

1 answer:

prisoha [69]3 years ago

7 0

Answer:

1320

Step-by-step explanation:

This is a simple permutation.

Since you start with 12 people and there are 3 winners, after every winner the number pf people available to win decrease.

First, there are 12 people, then after the first win there are 11 people, and after the 2nd win, for the third win the there are 10 people.

Thus, to find the total number of combinations, you multiply:

12*11*10=1320

Thus, there are 1320 possible combinations

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7 - 14x = 2x - 5 This is hard

gizmo_the_mogwai [7]

Answer:

3/4 = x

Step-by-step explanation:

7 - 14x = 2x - 5

+14x +14x

_____________

7 =16x -5

+5 +5

__________-

12 = 16x

÷16 ÷16

__________

12/16 = x

-or-

3/4 = x

Hope this helped :D

6 0

3 years ago

Read 2 more answers

Pls help I’ll mark brainliest

Pavel [41]

Answer:

2=72 4=148 6=222 10=370 15=555 16=592

sorry about the second part i didnt see it

5 0

3 years ago

Read 2 more answers

The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. (

Vinvika [58]

Answer:

a) $P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

b) $z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

$X \sim N(106,0.3)$

Where $\mu=106$ and $\sigma=0.3$

Part a

We are interested on this probability

$P(X>106.11)$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And using this formula we got:

$P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score we got:

$z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

6 0

3 years ago

You need to solve a system of equations. You decide to use the elimination

denis-greek [22]

Answer:

it is c it is c it is c it is c

4 0

3 years ago

a bastetball is passed through the air. The height h of the ball in feet after the distance d in feet the ball travels horizonta

Ksenya-84 [330]

You want the (positive) distance when the height is 0, 0= -d^2 + 10d +5. You would factor that out(You'd get radicals), and the final answer would be 5±30−−√ You'd take the only positive one of the two, 5 + srt(30) I hope I did that right :/

3 0

4 years ago