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Degger [83]
3 years ago
10

Fiona solved the equation shown.

Mathematics
2 answers:
LenaWriter [7]3 years ago
4 0

Answer:

Simplify by combining like terms

Step-by-step explanation:

elena55 [62]3 years ago
3 0

Answer:

A on edge 2020

Step-by-step explanation:

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PLEASE HELP I WILL GIVE BRAINLIEST!!
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Answer:

what is the question

Step-by-step explanation:

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The slope point equation of a line passing through the points (-3, -1) and (2, -6) is:
evablogger [386]

Answer:

y = -1x -4

Step-by-step explanation:

The point slope equation is y - y1 = m(x -x1).

You will have to plug in the points (-3, -1) and (2, -6).

y - (-1) = m (x - (-3))

To find "m", find y over x.

m = (y2 - y1) / ( x2 - x1)

m = (-6 + 1)/(2 + 3)

m = -5/5

m = -1

Then plug in "m"

y + 1 = -1(x + 3)

then distribute the "m" into the parenthesis and isolate y or subtract 1 from both sides.

y + 1 = -1x - 3

y = -1x -4

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3 years ago
On Monday Ethan sends an email to 3 friends the next day each of the 3 friends forward the email to 3 friends and so on as shown
sergey [27]

Answer: 12 or 9

Step-by-step explanation:

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3 years ago
Write an equation perpendicular to the x axis and contains the points (9,-2)
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X=9
so simple
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3 years ago
The Insurance Institute reports that the mean amount of life insurance per household in the US is $110,000. This follows a norma
nata0808 [166]

Answer:

a) \sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85

b) Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

c) P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)

And we can use the complement rule and we got:

P(Z>0.354) = 1-P(Z

d) P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)

And we can use the complement rule and we got:

P(Z>-1.768) = 1-P(Z

e) P(100000< \bar X

And we can use the complement rule and we got:

P(-1.768

Step-by-step explanation:

a. If we select a random sample of 50 households, what is the standard error of the mean?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the amount of life insurance of a population, and for this case we know the distribution for X is given by:

X \sim N(110000,40000)  

Where \mu=110000 and \sigma=40000

If we select a sample size of n =35 the standard error is given by:

\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85

b. What is the expected shape of the distribution of the sample mean?

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

c. What is the likelihood of selecting a sample with a mean of at least $112,000?

For this case we want this probability:

P(X > 112000)

And we can use the z score given by:

z= \frac{\bar X  -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)

And we can use the complement rule and we got:

P(Z>0.354) = 1-P(Z

d. What is the likelihood of selecting a sample with a mean of more than $100,000?

For this case we want this probability:

P(X > 100000)

And we can use the z score given by:

z= \frac{\bar X  -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)

And we can use the complement rule and we got:

P(Z>-1.768) = 1-P(Z

e. Find the likelihood of selecting a sample with a mean of more than $100,000 but less than $112,000

For this case we want this probability:

P(100000

And we can use the z score given by:

z= \frac{\bar X  -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

P(100000< \bar X

And we can use the complement rule and we got:

P(-1.768

8 0
3 years ago
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