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solong [7]
2 years ago
13

In an arithmetic sequence, a1=5 and a6=-5. Determine an equation for an, the nth term of this sequence.

Mathematics
1 answer:
GalinKa [24]2 years ago
6 0

Answer: 7 - 2n

Step-by-step explanation:

a1 = 5

a6 = -5 = a + (n - 1)d = a + (6 - 1)d

a + 5d = -5

Since a1 = 5

5 + 5d = -5

5d = -5 - 5

5d = -10

d = -10/5

d = -2

Therefore, the equation to calculate the nth term of this sequence will be:

= a + (n-1)d

= a + (n - 1)-2

= 5 -2n +2

= 7 - 2n

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How do i solve this
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Replace g for -2 and h for 5.

(2(-2) + 9(5) -5) - (6(-2) - 4(5) +2)

Taking this one at a time,
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4 0
3 years ago
What is the solution to the equation?
AleksandrR [38]

Solution of the equation: x=6\frac{1}{2}

Step-by-step explanation:

The equation that we have to solve in this problem is:

13\frac{3}{4}+x=7\frac{1}{4}

The first step to do is to rewrite the mixed fractions as improper fractions. We have:

13\frac{3}{4}=\frac{13\cdot 4+3}{4}=\frac{52+3}{4}=\frac{55}{4}

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7\frac{1}{4}=\frac{7\cdot 4+1}{4}=\frac{29}{4}

So the equation becomes

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Now we multiply by 4 each term on both sides, and we get

29+4x=55

Now we subtract 29 from both sides,

4x=55-29=26

And finally, we divide both sides by 4:

x=\frac{26}{4}=\frac{13}{2}=6\frac{1}{2}

Learn more about equations:

brainly.com/question/11306893

brainly.com/question/10387593

#LearnwithBrainly

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