The volume of cylinder shaped trash can is 4698 cubic inches, if the trash can has a height of 24.90 inches and a diameter of 15.50 inches.
Step-by-step explanation:
The given is,
Trash can has a height of 24.90 inches
Diameter of 15.50 inches
Step:1
Formula to calculate the volume of cylinder,
.............................(1)
Where, r - radius of cylinder
h - Height of cylinder
From given,
h - 24.90 inches
D - 15.50 inches
Diameter to radius conversion,


r = 7.75 inches
Equation (1) becomes,


(∵
)
= 4698.42
≅ 4698 cubic inches
Volume of trash can, V = 4698 cubic inches
Result:
The volume of cylinder shaped trash can is 4698 cubic inches, if the trash can has a height of 24.90 inches and a diameter of 15.50 inches.
Wow the answer is b because you secelted it
We need to start from the innermost parenthesis and work our way out.
The first parenthesis is
. These are not like terms because one involves a variable, while the other is a constant term. Two terms are summable if they involve the same power(s) of the same variable(s).
So, we can take one step outwards, and we arrive to the square brackets. We have

and 2z and -13z are like terms, so we can sum them:

Finally we arrive to the whole expression, which is

Because, again, 5z and 11z were like terms.
If (y-1) is a factor of f(y), f(y)=0 when y=1. So if you find that f(1)=0, then (y-1) is a factor of f(y).
f(y)=y^3-9y^2+10y+5
f(1)=1-9+10+5=7
Since f(1)=7, (y-1) is not a factor.
So use cancelation
multiply first equation by 2
2x+8y=10
times 2
4x+16y=20
now add
4x+16y=20
<u>-4x-9y=-13 +
</u>0x+7y=7
7y=7
divide by 7
y=1
subsittue
2x+8y=10
2x+8(1)=10
2x+8=10
subtract 8 from both sides
2x=2
divide by 2
x=1
x=1
y=1
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