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Studentka2010 [4]
3 years ago
15

Of the 120 apartments in a building, 75 have been scheduled to receive new carpet. What fraction of the apartments have not been

scheduled to receive new carpet?
Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0

Hello!

To find the fraction of the apartments that have not been scheduled to receive new carpet, we need first need find the number of apartments not receiving new carpet, by subtracting the total amount of apartments, by the 75 that have been scheduled.

120 - 75 = 45 apartments

Next, we need to create a fraction. Since 45 out of 120 apartments not are scheduled to get new carpeting, the fraction of these values is 45/120. This can be reduced to 3/8.

Therefore, your final answer is 45/120, simplified to 3/8.

Sever21 [200]3 years ago
5 0

There are 120 apartments in all. 75 are scheduled to receive new carpet.

The question is asking for the fraction of the apartments that have not been scheduled to recieve new carpet.

First, subtract 75 from 120:

120 - 75 = 45

<em>45 apartments have not been scheduled</em>.

Place the part (45) over the whole

45/120, or 3/8 of the apartments have not been scheduled.

hope this helps

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Answer:

yes

Step-by-step explanation:

well plug it in: y=6x -> y=6(3/9) and solve, yes if theres a slope of 1

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In the lottery game known as 6/36, a player picks six numbers from 1 to 36. (a) How many different ways are there for the player
Goryan [66]

Answer:

Step-by-step explanation:

Part A

This is a combination problem. Order does not matter.

36C6

36!/(30! 6!)

36 * 35 * 34 * 33 * 32 * 31/ 6!

1402410240/6!

1947792

Part B

1 / (36C6)

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52 – 4 &gt; – 29 AND – 12 + 6 &gt; 2<br> Solve and give answer in interval notation
BlackZzzverrR [31]

Answer:

wait huh?im confused lol

Step-by-step explanation:

6 0
3 years ago
A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has
ExtremeBDS [4]

Answer:

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

p_v =P(t_{(23)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=136 represent the sample mean

s=11 represent the sample standard deviation

n=24 sample size  

\mu_o =140 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=24-1=23  

Since is a one left tailed test the p value would be:  

p_v =P(t_{(23)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

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What is 2,400,000 in word form
Kruka [31]
Two million, four hundred thousand.
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3 years ago
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