I can't see the problem so repost it and tag me in it
Answer:
The probability is 0.8
Step-by-step explanation:
The key to answering this question is considering the fact that the two married employees be treated as a single unit.
Now what this means is that we would be having 8 desks to assign.
Mathematically, the number of ways to assign 8 desks to 8 employees is equal to 8!
Now, the number of ways the couple can interchange their desks is just 2 ways
Thus, the number of ways to assign desks such that the couple has adjacent desks is 2(8!)
The number of ways to assign desks among all six employees randomly is 9!
Thus, the probability that the couple will have adjacent desks would be ;
2(8!)/9! = 2/9
This means that the probability that the couple have non adjacent desks is 1-2/9 = 7/9 = 0.77778
Which is 0.8 to the nearest tenth of a percent
The 68-95-99.7 rule tells us 68% of the probability is between -1 standard deviation and +1 standard deviation from the mean. So we expect 75% corresponds to slightly more than 1 standard deviation.
Usually the unit normal tables don't report the area between -σ and σ but instead a cumulative probability, the area between -∞ and σ. 75% corresponds to 37.5% in each half so a cumulative probability of 50%+37.5%=87.5%. We look that up in the normal table and get σ=1.15.
So we expect 75% of normally distributed data to fall within μ-1.15σ and μ+1.15σ
That's 288.6 - 1.15(21.2) to 288.6 + 1.15(21.2)
Answer: 264.22 to 312.98
A should be B because the other option don’t make sense and part B I got 4 11/12
Answer:
171
Step-by-step explanation:
First you plug -4 into the g(x) equation
g(-4)= 1-3(-4)
Use pemdas
g(-4)= 1+12
g(-4)= 13
Next you plug 13 into the f(x) equation
f(13)= 13^2 + 2
First you do 13^2=169
Add 2 and you get 171
