Answer:
If the question does not limit man to produce only one model of club, then the maximized profit of every condition produced under 50 sets daily will be all model A exclusive. such as $60 x 50 (model A) , even just produce 49 set that day, the maximal profit is still $60 x 49.
Step-by-step explanation:
If the question does not limit man to produce only one model of club, then the maximized profit of every condition produced under 50 sets daily will be all model A exclusive. such as $60 x 50 (model A) , even just produce 49 set that day, the maximal profit is still $60 x 49.
Re-consider the logic of the question ....
The first one because the left bound is included [ and the right one is not )
So you would multiply the length times width!
Answer:
Adjacent
Step-by-step explanation:
Because supplementary angles make 180 degrees, complementary make 90 degrees, vertical angles are pairs of opposite angles made by two intersecting lines.
Answer:
The area of the parallelogram is 55 square unit.
Step-by-step explanation:
The area of a parallelogram is
![A=\frac{1}{2}\times base\times height](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height)
It is given that the vertices of the parallelogram are P(-2, -5), Q(9, -5), R(1, 5), S(12, 5).
Plot these points on a coordinate plane, and draw a perpendicular on PQ from the point R.
From the graph is clear that length of PQ is 11 and the height of the parallelogram is 10. So, the area of a parallelogram is
![A=\frac{1}{2}\times 11\times 10](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%2011%5Ctimes%2010)
![A=55](https://tex.z-dn.net/?f=A%3D55)
Therefore the area of the parallelogram is 55 square unit.