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Svetach [21]
3 years ago
8

Find the slope -2/3, 2/3,3/2,-3/2

Mathematics
1 answer:
Nonamiya [84]3 years ago
5 0

Answer:

-\frac{3}{2}

Step-by-step explanation:

You count up 3 units. Then you count to the left 2 units. It is negative because the line is slanted to the left.

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What is 3 as a fraction? An the 3 isn't in percentage.... its just three.
BlackZzzverrR [31]

3/1

Hope this helps you!

6 0
3 years ago
Read 2 more answers
If G is the circumcenter of triangle ABC, find CG and FB. Round to the nearest tenth if necessary.
Stolb23 [73]

9514 1404 393

Answer:

  CG = 19

  FB = 14.7

Step-by-step explanation:

The circumcenter is equidistant from the triangle vertices, so GA = GB = GC.

The length of GA is given, so we have ...

  GA = 19 = CG

__

Then the Pythagorean theorem can be used to find FB.

  FB² +FG² = GB²

  FB² = GB² -FG² = 19² -12² = 217

  FB = √217 ≈ 14.7

3 0
3 years ago
What is the value of x?
Scorpion4ik [409]

Answer:

46

Step-by-step explanation

134 + x has to equal 180 because it makes a straight line.

So you do 180 - 134 to get 46

7 0
4 years ago
X + (-3) = -7<br> X=<br> Answer here<br> I
tatiyna

Answer:

x=-4

Step-by-step explanation:

x-3=-7

x=-7+3

x=-4

3 0
4 years ago
Read 2 more answers
What is the leading coefficient of a third degree polynomial function that has an output of 1,272 when x=2, and has zeros of −6,
Gre4nikov [31]

Answer:

<em>The leading coefficient is 3</em>

Step-by-step explanation:

<u>Polynomials</u>

Given the roots of a polynomial x1,x2,x3, it can be expressed as:

p(x)=a(x-x1)(x-x2)(x-x3)

Where a is the leading coefficient.

We are given the roots x1=-6, x2=7i, x3=-7i, thus:

p(x)=a(x+6)(x-7i)(x+7i)

Operating the product of the conjugated imaginary roots:

p(x)=a(x+6)(x^2+49)

Knowing p(2)=1,272 we can find the value of a

p(2)=a(2+6)(4+49)=1,272

Operating:

a(8)(53)=1,272

424a=1,272

Solving:

a=1,272/424

a=3

The leading coefficient is 3

6 0
3 years ago
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