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ziro4ka [17]
3 years ago
9

How many 1/10s in 2 3/5

Mathematics
1 answer:
Umnica [9.8K]3 years ago
5 0

It'd be clearer if you'd write:  "How many tenths are there in 2 3/5?"

2 3/5        13/5

---------- = ---------- = 26

(1`/10)        1/10

There are 26 tenths in 2 3/5.

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Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4?
ivann1987 [24]

f(x)= -99.4x + 198.8

f(1) = -99.4*1 + 198.8 = 99.4

f(2) = -99.4*2 + 198.8 = 0

f(3) = -99.4*3 + 198.8 = -99.4

f(4) = -99.4*4 + 198.8 = -198.8

5 0
3 years ago
Please help me solve this problem!!
skad [1K]

Answer:

the coordinate of B is (-1;1)

4 0
3 years ago
What is the surface area of a cone with a radius of 5 and a height of 21 in terms of pi PLZ HELP
klio [65]

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Step-by-step explanation:

3 0
3 years ago
The entire graph of the function g is shown in the figure below.
marusya05 [52]

The domain of the function is [-4, 4) and the range of the function is [-5, 2)

<h3>How to determine the domain and the range of the function?</h3>

<u>The domain</u>

As a general rule, it should be noted that the domain of a function is the set of input values or independent values the function can take.

This means that the domain is the set of x values

From the graph, we have the following intervals on the x-axis

x = -4 (closed circle)

x =4 (open circle)

This means that the domain of the function is [-4, 4)

<u>The range</u>

As a general rule, it should be noted that the range of a function is the set of output values or dependent values the function can produce.

This means that the range is the set of y values

From the graph, we have the following intervals on the y-axis

y = -5 (closed circle)

y = 2 (open circle)

This means that the range of the function is [-5, 2)

Read more about domain and range at:

brainly.com/question/10197594

#SPJ1

7 0
2 years ago
In the equation 9^2 x 27^3 = 3^x, what is the value of x? <br> Show your work on scratchpaper
IceJOKER [234]

Answer:

x=13

Step-by-step explanation:

9^2 * 27^3 = 3^x

We need to get each term with a base of 3

9^2 = (3^2) ^2

We know that a^b^c = a^(b*c)

(3^2) ^2 = 3^(2+2) = 3^4

27^3 = (3^3) ^3 = 3^(3*3) = 3^9

Replacing these in the original equation

3^4 * 3^9 = 3^x

We know that a^b *a^c = a^(b+c)

3^4 * 3^9  =3^(4+9) = 3^13 = 3^x

The bases are the same, so the exponents must be the same

x=13

7 0
3 years ago
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