You haven't listed the possible solutions, so in the immediate present I can help only by suggesting that you try solving this system and checking your own answers thru subst. into the given equations.
Please be sure to use "^" to indicate exponentiation, as shown below:
<span>4x2 + 9y2 = 72 should be 4x^2 + 9y^2 = 72 (this is the eq'n of an ellipse)
x - y2 = -1 should be x - y^2 = -1 (this is the equation of a parabola)
We must eliminate either x or y. I will solve the 2nd equation for y^2 and subst. the result into the first eq'n.:
y^2 = x+1. Subst. this into the first equation,
</span>4x^2 + 9y^2 = 72 becomes 4x^2 + 9(x+1) = 72.
Expanding, 4x^2 + 9x + 9 = 72, or 4x^2 + 9x - 63 = 0
We must solve this quadratic equation to obtain the x-coordinates of possible solutions of the original system of equations.
-9 plus or minus 33
After some work, we get x = ------------------------------
8
So x = 24/8 = 3, or x = -42/8 = -5 1/4 or -21/4
Check out x=3. We already have the relationship y^2 = x+1. If x = 3, then y^2 = 3+1 = 4, and y is plus or minus 2.
Two possible solutions of the original set of equations are thus (3,2) and (3,-2). You MUST check both solutions thru substitution to determine whether they satisfy the original equations or not.
Answer:
What is the question?
Step-by-step explanation:
Please give me brainliest :)
Answer:
Probability of a prime number = 2/5.
Probability of last number being odd = 3/5.
Step-by-step explanation:
There are 2 prime numbers (5 and 7) in the 5 numbers ( 5, 6, 7, 8, 9).
So Prob(Prime number being first) = 2/5.
There are 3 odd numbers and 2 even so:
Possible combinations of Odd (O) and Even (E) numbers with last number being Odd are:
OOO, EEO, OEO or EOO.
Prob (OOO) = 3/5 * 1/2 * 1/3 = 3/30 = 1/10.
Prob(EEO) = 2/5 * 1/4 = 1/10.
Prob(OEO) = 3/5 * 1/2* 2/3 = 6/30 = 1/5.
Prob(EOO) = 2/5 * 3/4 * 2/3 = 12/60 = 1/5.
Therefore the probability of the last number being odd =
1/10 + 1/10 + 1/5 + 1/5
= 3/5 (answer).
Sam and Erica are correct because if you multiply you l and w by two you would get the perimeter and also you can do the value of one w and multiply it by two and also the L hope it helps
Answer:
D: A rhombus is always a parallelogram
Step-by-step explanation:
A rhombus is a quadrilateral, and it is also a parallelogram. However, a parallelogram is not always a rhombus.