as AB || DE then
angle BAE = angle AED
so angle AED = 70
as AD = AE then
angle AED = angle ADE = 70
now in a triangle
angle DAE + Angle ADE + angle AED = 180
angle DAE + 70 + 70 = 180
angle DAE = 180 - 140 = 40
Answer:
D. d = sqrt( ( x2-x1)^2 + (y2-y1)^2)
C. d = sqrt( ( x1-x2)^2 + (y1-y2)^2)
B. d = sqrt( (|x2-x1|^2 + |y2-y1|^2)
Step-by-step explanation:
Given two points (x1, y1) and (x2,y2) we can find the distance using
d = sqrt( ( x2-x1)^2 + (y2-y1)^2)
The order of the terms inside the square doesn't matter
d = sqrt( ( x1-x2)^2 + (y1-y2)^2)
When we are squaring are term, we can take the absolute value before we square and it does not change the value
d = sqrt( (|x2-x1|^2 + |y2-y1|^2)
When you want to find zeros of rational expression you need to find at which points numerator is equal to zero. In this case, we have the product of three expressions.

A product is equal to zero whenever one of the factors is equal to zero.
That means that zeros of our functions are:
1)

2)


3)


The final answer is a. Function has zeros at (0, 1, -11).
Answer:
The value of b is 3
Step-by-step explanation:
mx is the slope and b is the y intercept. I hope this helps!