Answer:
$3100 is invested at 9%
$4900 is invested at 11%
Step-by-step explanation:
Let's take "x" be the amount invested at 9%.
(x + 1800) is invested in another account at 11%.
The interest amount earned by the two accounts is $818.
Here we can use the simple interest formula and find the amount invested in each account.
Simple interest (I) = , where P- is the principal , N is the number of years and R is the interest rate.
Simple interest =
0.09x + 0.11(x+1800) = 818
Now we have to simplify and find the value of x .
Use the distributive property and simplify the second term.
0.09x + 0.11x + 198 = 818
0.2x + 198 = 818
0.2x =818 - 198
0.2x = 620
x = 620/0.2
x = 3100.
So $3100 is invested at 9%
x + 1800 = 3100 + 1800
= $4900
$4900 is invested at 11%
Hope this helped.
Answer:
the lines are neither perpendicular or parallel
Answer: the company should invest $12191 each week
Step-by-step explanation:
The amount that the company needs is $5,400,000
We would apply the periodic interest rate formula which is expressed as
P = a/[{(1+r)^n]-1}/{r(1+r)^n}]
Where
P represents the weekly payments.
a represents the amount that the company needs
r represents the rate.
n represents number of weekly payments. Therefore
a = 5,400000
There are 52 weeks in a year
r = 0.079/52 = 0.0015
n = 52 × 14 = 728
Therefore,
P = 5400000/[{(1+0.0015)^728]-1}/{0.0015(1+0.0015)^728}]
5400000/[{(1.0015)^728]-1}/{0.0015(1.0015)^728}]
P = 5400000/{2.98 -1}/[0.0015(2.98)]
P = 5400000/(1.98/0.00447)
P = 5400000/442.95
P = $12191
