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FrozenT [24]
3 years ago
5

PLEASE HELP & SHOW WORK , ITS URGENT

Mathematics
2 answers:
frosja888 [35]3 years ago
8 0

Answer:

I haven't gone this through yet but Ima help as much as possible. I know for sure you need to use the Area formula of Octagon and Perimeter and substitute the values. Once you substitute you gonna solve it like any other equation. I hope I helped ~

lara31 [8.8K]3 years ago
6 0

Answer:

D. 80 ft

Step-by-step explanation:

substitute the known values into the equation for area

a = 5

area = 200

200=(5*P)/2

multiply both sides by 2 which gives you

400=5*P

then divide both sides by 5 to give you

80 = P

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185% as a fraction in simplest form
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First 8 is added to me , then j am multiplied by 6.then 40 is subtracted from me .Finally I am divided by 10. The result is 11.
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3 years ago
Current rules for telephone area codes allow the use of digits​ 2-9 for the first​ digit, and​ 0-9 for the second and third​ dig
Anna35 [415]

Using the fundamental counting theorem, we have that:

  • 648 different area codes are possible with this rule.
  • There are 6,480,000,000 possible 10-digit phone numbers.
  • The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

  • 8 options for the first digit.
  • 9 options for the second and third.

Thus:

8 \times 9 \times 9 = 648

648 different area codes are possible with this rule.

For the number of 10-digit phone numbers:

  • 7 digits, each with 10 options.
  • 648 different area codes.

Then

648 \times 10^7 = 6,480,000,000&#10;

There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

5 0
2 years ago
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