Let's say a = number of ordered soups, b = number of ordered sandwiches.
Then 4.5a + 7.75b = 113.50, and a and b are integers between 0 and 18 inclusive.
How do we tackle this? If all ordered soup, the cost would be $81, so we'll have at least 4 sandwiches. If all ordered sandwich, the cost would be $139.5, so at most 15 sandwiches were ordered. You also know an even number of sandwiches was ordered, to let the price end at 50 cent.
If you brute-force from 4,6,8,10,12 to 14 sandwiches, you find the answer at 10 sandwiches and 8 soups.
10*7.75 + 8*4.50 = 113.50
Answer:
ABC is similar to ADE because ABC and ADE have similar degree angles
Step-by-step explanation:
Sorry if this is wrong.
Answer:
B decrease
Step-by-step explanation:
First, lets put the numbers in order from greatest to least.
10 9 9 8 6 4 4
Second, let's find the median without number 1. (The median is in bold.)
10 9 9 8 6 4 4
Third, let's add the number 1.
10 9 9 8 6 4 4 1
Fourth, let's find the median with the number 1.
10 9 9 8 6 4 4 1
Since there are two numbers in the middle let's find the average between them.
8+6=14
14/2= 7
Last, let's compare the two medians.
8>7
So when you add the number 1 the median decreases. So your answer is B decrease
<u>Answer</u><u>:
</u>
Required integer is -12.
Step-by-step explanation:
Given:
Required number is integer.
Required integer is less than zero
greater than -13.
When number is substracted from -11, result is positive.
To Find:
The integer=?
Solution:
Lets assume required integer = x
As Required integer is less than zero and greater than -13 ,
-13 < x < 0 ------(1)
Also when number is subtracted from -11, result is positive.
=> -11 – x > 0
=> -11 > x -------(2)
So form 1 and 2
-13 < x < -11 that is x is an integer which is less than -11 and greater than -13. There is only one integer between -13 and -11 that is -12.
Hence required integer is -12.
If you do x- number of water cups 1 over 8 will equal 32 over x ,x=256 so 256
if this makes any sense if not ill try better to explain
