Ax+bx−c=0
Step 1: Add c to both sides.
ax+bx−c+c=0+c
ax+bx=c
Step 2: Factor out variable x.
x(a+b)=c
Step 3: Divide both sides by a+b.
x(a+b)a+b=ca+b
x=ca+b
The answer is 60 bc -3 x -4 is 12, and 12x5 is 60
well, first off, let's notice that we have a trapezoid with a rectangle inside it, so the rectangle is really "using up" area that the trapezoid already has.
now, if we just get the area of the trapezoid, and then the area of the rectangle alone, and then subtract that area of the rectangle, the rectangle will in effect be making a hole inside the trapezoid's area, and what's leftover, is the shaded section, that part the hole is not touching.
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h&=height\\ a,b&=\stackrel{parallel~sides}{bases} \\\cline{1-2} h&=8\\ a&=16\\ b&=8 \end{cases}\implies A=\cfrac{8(16+8)}{2}\implies A=96 \\\\\\ \stackrel{\textit{area of the rectangle}}{(5\cdot 3)\implies 15}~\hfill \stackrel{~\hfill \textit{shaded area}}{\stackrel{\textit{trapezoid}}{96}~~ - ~~\stackrel{\textit{rectangle}}{15}~~ = ~~81}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%26%3Dheight%5C%5C%20a%2Cb%26%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%20%5C%5C%5Ccline%7B1-2%7D%20h%26%3D8%5C%5C%20a%26%3D16%5C%5C%20b%26%3D8%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B8%2816%2B8%29%7D%7B2%7D%5Cimplies%20A%3D96%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20rectangle%7D%7D%7B%285%5Ccdot%203%29%5Cimplies%2015%7D~%5Chfill%20%5Cstackrel%7B~%5Chfill%20%5Ctextit%7Bshaded%20area%7D%7D%7B%5Cstackrel%7B%5Ctextit%7Btrapezoid%7D%7D%7B96%7D~~%20-%20~~%5Cstackrel%7B%5Ctextit%7Brectangle%7D%7D%7B15%7D~~%20%3D%20~~81%7D)