Some reasons to use a stem and leaf plot

1 answer:

7 0

Stem-and-leaf plots are a method for showing the frequency with which certain classes of values occur. You could make a frequency distribution table or a histogram for the values, or you can use a stem-and-leaf plot and let the numbers themselves to show pretty much the same information.

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∠A and ∠B are complementary angles. The measure of ∠A=4x° and the measure of ∠B=50°. Find m∠A. * i dont understand can someone h

jolli1 [7]

Answer:

m>a is 40

Step-by-step explanation:

4x + 50 = 90

4x = 40

x = 10

10*4 = 40

M>A = 40

3 0

3 years ago

Find the volume and round to the nearest tenth as needed

monitta

Answer: 1962.4 cubic mm

Step-by-step explanation:

The volume of the larger cone is $V=\frac{1}{3}(\pi)(10^{2})(20)=\frac{2000\pi}{3}$

The volume of the smaller cone is $V=\frac{1}{3}(\pi)(3^{2})(14)=42\pi$ .

So, the volume is $\frac{2000\pi}{3}-42\pi \approx \boxed{1962.4}$

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2 years ago

Jonah is thinking of a 2 digit number. it is a multiple of 6 and 12. it is a factor of 108. the sum of its digits is 9. what num

Goshia [24]

Dear Joshua10, the answer is 36. 36 is two digits, 3 and 2, it is a multiple of 6 and 12: 6 times 6 equals 36 and 12 times 3 equals 36, it is a factor of 108: 36 times 3 equals 108, and 36 has digits that equal to 9: 3 plus 6 equals 9.

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2 years ago

an electric can opener is worth 38 dollars when it is new. After each year it is worth half what it was the previous year. What

BigorU [14]

1 Year: 19
2 Years: 9.50
3 Years: 4.75
4 Years: 2.38 (2.375, but rounded)

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2 years ago

How do I do 8b(ii) ? Please help me thank you!

Mila [183]

Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.

7 0

3 years ago