a. Expressing y in terms of x, y = 20/(x + 3)
b. When x = 5, the value of y is 2.5
The question has to do with inverse variation.
<h3>What is inverse variation?</h3>
Inverse variation is variation in which one quantity varies inversely as the other.
<h3>a. How to express y in terms of x?</h3>
Given that y is inversely as x + 3 and that y = 4 when x = 2.
Since y varies inversely as x + 3, we have
y ∝ 1/(x + 3)
y = k/(x + 3)
When y = 4, x = 3. So
y = k/(x + 3)
4 = k/(2 + 3)
4 = k/5
k = 4 × 5
k = 20
So, y = k/(x + 3)
y = 20/(x + 3)
So, expressing y in terms of x, y = 20/(x + 3)
<h3>b. Find the value of y when x = 5.</h3>
Since y = 20/(x + 3)
Substituting x = 5 into the equation, we have
y = 20/(x + 3)
y = 20/(5 + 3)
y = 20/8
y = 5/2
y = 2.5
So, when x = 5, the value of y is 2.5
Learn more about inverse variation here:
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