3 years ago

Which point approximates the solution for Tenisha’s system of equations?

Mathematics

1 answer:

algol [13]3 years ago

6 0

Where is Tenisha's system?

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Please Help Quickly!!!<br><br> Find the limit if f(x) = x^3

jeka94

Answer:

Option b. 12

Step-by-step explanation:

This exercise asks us to find the derivative of a function using the definition of a derivative.

Our function is $f(x) = x^{3}$ . Therefore:

$f(2+h) = (2+h)^{3}$

$f(2) = (2)^{3} = 8$

Then:

$\lim_{h \to \0} \frac{f(2+h)-f(2)}{h}=\lim_{h \to \0} \frac{(2+h)^{3}-8}{h}$

Expanding:

$\lim_{h \to \0} \frac{(2+h)^{3}-8}{h} =\lim_{h \to \0} \frac{8+ h^{3} +6h(2+h) -8}{h} =\lim_{h \to \0} \frac{h^{3} +6h(2+h)}{h}$

$\lim_{h \to \0} \frac{h^{3}+ 6h(2+h)}{h} =\lim_{h \to \0} h^{2} + 6(2+h)$

Now, if x=0:

$\lim_{h \to \0} \frac{f(2+h)-f(2)}{h} = (0)^{2} +6(2+0) = 12$

4 0

3 years ago

solve 2x2 12x − 14 = 0 by completing the square. 2(x 6)2 = 26; x = −6 square root 13, x = −6 − square root 132(x 6)2 = 20; x = −

coldgirl [10]

Assuming that the blank space is a plus
2x^2+12x-14=0

isolate x
(2x^2+12x)-14=0
undistribute 2
2(x^2+6x)-14=0
take 1/2 of 6 and square and add negative and positive
2(x^2+6x+9-9)-14=0
factor perfect squrae
2((x+3)^2-9)-14=0
distribute
2(x+3)^2-18-14=0
2(x+3)^2-32=0
2(x+3)^2=32
divide 2
(x+3)^2=16
sqrt
x+3=+/-4
minus 3
x=+/-4-3
x=-7 or 1
2nd to last option

5 0

4 years ago

The function f(x)=x+n is a polynomial? true or false.

Andrew [12]

False I don’t really know why

5 0

3 years ago

Find the difference of 7,000,000 and 356,217

belka [17]

The answer to your question is 6,643,783

8 0

4 years ago