Answer:
The bill excluding tax is $31.21 and the 20% tip was $6.24.
If period of

is one-half the period of

and
<span>

has a period of 2π, then

and

.
</span>
To find the period of sine function

we use the rule

.
<span /><span />
f is sine function where f (0)=0, then c=0; with period

, then

, because

.
To find a we consider the condition

, from where

.
If the amplitude of

is twice the amplitude of

, then

has a product factor twice smaller than

and while period of

<span> </span> is 2π and g(0)=0, we can write

.
Answer:
x^5y^5
Step-by-step explanation:
<em>here's</em><em> your</em><em> solution</em>
=> if base are same then power get added in multiplication
=> so, x^2 * y^4 * x^3 * y^1
=> x^2 * x^3 * y^4 * y^1
=> x^5*y^5
hope it helps