3 years ago

What is 949 to the nearest hundred

1 answer:

4 0

The answer. an be wrote Nine Hundred or 900

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olchik [2.2K]

I believe the answer is 0

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ruslelena [56]

I know hwo can help you

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KonstantinChe [14]

Answer:

Step-by-step explanation:

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3 years ago

notsponge [240]

Answer:

The most common distance that Larry biked was of 6 Km.

Step-by-step explanation:

The most common distance that Larry biked is the number, in Km, which appears most frequently in this table.

The number which appears the most frequently is:

6 km

This means that the most common distance that Larry biked was of 6 Km.

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3 years ago

forsale [732]

$1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}$

Step-by-step explanation:

The given equation is $4x^{2}-8x-1$

Let $a$ be the coefficient of $x^{2}$

Let $b$ be the coefficient of $x$

Let $c$ be the constant.

Then the roots α,β for the equation $ax^{2}+bx+c$ are $\dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}$

So,α= $\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}$

β= $\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}$ .

So the roots are $1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}$

5 0

3 years ago