8 times the difference of u and 10

Write the value of the expression 3^3/3^6

scZoUnD [109]

Answer:

When dividing two values with the same base, we simply subtract the first exponent by the second and keep the original base. 3^3-6=3^-3. This equals out to be 1/27.

Step-by-step explanation:

6 0

3 years ago

Can someone please give me the answers to this? ... please ...

Hoochie [10]

Step-by-step explanation:

come on ! based on all the other questions that have been answered AND explained you should be able to find these answers yourself now. what is still unclear ?

distance between 2 points (x1, y1) and (x2, y2):

Pythagoras : c² = a² + b²

c is the connection between the 2 points (and which length we need to find).

c = sqrt(a² + b²)

a and b are differences of the x coordinates and the differences of the y coordinates of these 2 points.

a = x1 - x2

b = y1 - y2

this is simply because, when you look at the coordinate grid, these 3 items make a right-angled triangle.

don't worry about any negative values for a and b, as the square eliminates the negative sign.

midpoint between 2 points :

we could use Pythagoras again for this, but the end result is so simple, we can skip this.

at the end the coordinates of the midpoint of 2 points (x1, y1) and (x2, y2) are

((x1+x2)/2, (y1+y2)/2)

find the other endpoint (x2, y2), when you have one endpoint (x1, y1) and the midpoint (xm, ym) :

from above you know

xm = (x1+x2)/2

2×xm = x1 + x2

x2 = 2×xm - x1

and in the same way

ym = (y1+y2)/2

2×ym = y1 + y2

y2 = 2×ym - y1

and you can read a graph, right ?

if not it is high time to learn that very simple and basic skill :

the x coordinate of a point is how many units right (positive) or left (negative) from the center point it is.

the y coordinate of a point is how many units above (positive) or below (negative) from the center point it is.

the center point is always (0, 0).

so, what else do you need ?

I am very busy explaining things. I should not spend my little time doing the basic calculations for you (that I could train a monkey to do).

so, please, oil your brain machinery by following the instructions and formulas using the actual numbers and see how the results build out of this.

if you run into further problems, please ask me for additional explanations.

8 0

2 years ago

Round off square root of 120 to the nearest whole number?

Westkost [7]

Answer:

11

Step-by-step explanation:

for this question we can look at the whole answer for the square root of 120 which equals 10.9544511501

$\sqrt{120} = 10.9544511501$

now looking at our answer (10.9544511501) we want to find the nearest WHOLE NUMBER. in the current answer the whole number is 10, followed by many decimals.

10.9544511501

but to find the nearest whole number we have to round the place value BEFORE our whole number. (in this case the 9)

10.9544511501

we can now look at this highlighted section of our equation and think... is 10.9 closer to 11 or 10. well logically, to get to 11 from 10.9 we only have to go up by 0.1, rather than to get to 10, where you have to subtract 0.9.

10.9 + 0.1 = 11

10.9 - 0.9 = 10

But to make it easier, remember the rule:

the place value one place to the RIGHT of what you're rounding to, is what determines the new number. (in this case the .9)

and as any number 5 or above rounds up, we can say that our new number, rounded to the nearest whole number equals 11

10.9 rounded to the nearest whole number = 11

4 0

2 years ago

Help due today please

horsena [70]

Answer:

angle ABD =55 degree

angle BCD= 125 degree

Step-by-step explanation:

angle ABD and angle DBC are supplementary angles.

Hence, angle ABD +angle DBC = 180 --equation 1

angle ABD = (2x+15) ---equation 2

angle BCD = (4x+45) ------equation 3

ABD+DBC=180

(2x+15) + ( 4x+45 ) = 180

2x+4x+15+45=180

6x+60=180

6x=180-60

6x=120

x=120/6=20

angle ABD= 2x+15= 2(20) +15

=40+15= 55 degree

angle BCD= 4x+45 = 4(20) +45

= 80+45= 125 degree

Hence, angle ABD =55 degree

angle BCD= 125 degree

Hope this helps.

7 0

2 years ago

Factoring Trinomials

alexandr402 [8]

25 a² + 20 ab + 4 b²

for formula $a^x+bx^ky^k+cy ^{2k }$ find u,v such that: u.v = a

and u+v = b then group according to $(ax ^{2k} +ux^ky^k)+(vx^ky^k+cy ^{2k} )$

= $(25a^2+10ab)+(10ab+4b^2)$

factor out 5a from : $25a^2+10ab : 5a(2b+5a)$

factor out 2b from : $10ab+4b^2: 2b(2b+5a)$

= $5a(2b+5a) + 2b(2b+5a)$

factor out : $(5a+2b)$

= $(5a+2b)(5a+2b)$

Refine:

$(2b+5a)^2$

hope this helps!.

3 0

3 years ago