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3 years ago

15

Use the zero product property to find the solutions to the eqation 6x^2 -5x=56

1 answer:

nignag [31]3 years ago

8 0

Answer:

B. 7/2, -8/3

Step-by-step explanation:

Move all the terms to the left side and set them equal to zero. Then set each factor equal to zero.

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Maria bought a hat for $45.she had to sell them at a loss of 5%.find the selling price of the hat?

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£42.75
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3 years ago

How can you find f(2) if f(x) = -3x2 – 7?

nordsb [41]

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Step-by-step explanation:

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3 years ago

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3/4 - 5/8 <br><br><br> can someone plz tell answer

ss7ja [257]

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3 years ago

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The area of Ray’s rectangular living room, in square feet, can be found by using the expression 4(3x+3y). Use the distributive p

Greeley [361]

Answer:

Area = 72 square feet

Step-by-step explanation:

$4(3x+3y)$

Multiply the four to the values inside the parentheses to find the "equivalent expression"

$12x +12y$

Using the "equivalent expression" we found above, we now want to find the area of Ray's living room, in square feet if $x=2$ and $y = 4$

$12(2) + 12(4)$

$= 24 +48$

$= 72$

3 0

2 years ago

Please guys please pllease

klio [65]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

Let's calculate its discriminant :

$\qquad \sf \dashrightarrow \: 4 {u}^{2} + 16u + 41 = 40$

$\qquad \sf \dashrightarrow \: 4 {u}^{2} + 16u + 41 - 40 = 0$

$\qquad \sf \dashrightarrow \: 4 {u}^{2} + 16u + 1 = 0$

Here, if we equate it with general equation,

a = 4

b = 16

c = 1

$\qquad \sf \dashrightarrow \: disciminant = {b}^{2} - 4ac$

$\qquad \sf \dashrightarrow \: d = (16) {}^{2} - (4 \times 4 \times 1)$

$\qquad \sf \dashrightarrow \: d = (16) {}^{2} - (16)$

$\qquad \sf \dashrightarrow \: d = 16(16 - 1)$

$\qquad \sf \dashrightarrow \: d = 16(15)$

$\qquad \sf \dashrightarrow \: d = 240$

Now, since discriminant is positive ; it has two real roots ~

The roots are :

$\qquad \sf \dashrightarrow \: u = \dfrac{ - b \pm \sqrt{ d } }{2a}$

$\qquad \sf \dashrightarrow \: u = \dfrac{ - 16\pm \sqrt{ 240 } }{2 \times 4}$

$\qquad \sf \dashrightarrow \: u = \dfrac{ - 16\pm 4\sqrt{ 15 } }{8}$

$\qquad \sf \dashrightarrow \: u = \dfrac{ 4(- 4\pm \sqrt{ 15 }) }{8}$

$\qquad \sf \dashrightarrow \: u = \dfrac{ - 4\pm \sqrt{ 15 } }{2}$

So, the required roots are :

$\qquad \sf \dashrightarrow \: u = \dfrac{ - 4 - \sqrt{ 15 } }{2} \: \: and \: \: \dfrac{ - 4 + \sqrt{15} }{2}$

4 0

2 years ago

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