Answer:
3x - 11
Step-by-step explanation:
x + 5/ 3x-11
3x - 11 is the quotient
Assume N students
Student 1 can get (n-1) papers
Student 2 can get (n-1) papers
Student 3 can get (n-1) papers
etc
Student N can get (n-1) papers
So for N students you can have N(n-1)
Answer:
$( 51x^2 + x + 29).
Step-by-step explanation:
Amount she had left = original amount - amount spent on the gloves
= 62x^2 + x - 4 - (11x^2 - 33) (note we place the amount spent on gloves in parentheses because we have to subtract the whole amount)
Now we distribute the negative over the parentheses:
= 62x^2 + x - 4 - 11x^2 + 33 ( note - 33 becomes -33*-1 = +33)
Now simplifying like terms:
= 51x^2 + x + 29 (answer).
Answer:
Complete solution is given in the images attached below for better demonstration
I think D is the correct answer
