All categories

3 years ago

What is the fraction form of 4.03

Mathematics

1 answer:

guapka [62]3 years ago

4 0

The fraction form would be 4 3/100

You might be interested in

The answer to question 21 please??

Ad libitum [116K]

Answer:

A = 1/2*(2 + 8)*4 + 1/2*(8 + 7)*2 = 35

35 * 2.25^2 = 177.2 ft² --> Answer c.

5 0

2 years ago

Read 2 more answers

A die is rolled. Write each answer as a fraction, decimal, and percent. Show your work.

dalvyx [7]

A. 1/6, .16666666, 16.6666666%
B. 4/6, .64, 64%
C. 5/6, .80, 80%

3 0

3 years ago

The measures of two sides of a triangle are 15 and 16. between what two numbers must the measure of the third side fall?

QveST [7]

If it is a right triangle and you given me adjacent and opposite the formula is
${r}^{2} = {x}^{2} + {y}^{2}$
third side = 21.93

if its not right triangle you need the angle to solve

6 0

3 years ago

Please include work!

geniusboy [140]

Answer:

x = ± 4

y = - 2

Step-by-step explanation:

y = 0.5x² - 10 ------------------------(I)

y = -x² + 14 ------------------------(II)

Substitute the y value in equation (II)

0.5x² - 10 = -x² + 14 {Add x² to both sides}

0.5x² + x² -10 = 14 {combine like terms}

1.5x² - 10 = 14 {Add 10 to both sides}

1.5x² = 14 + 10

1.5x² = 24 {Divide both sides by 1.5}

1.5x²/1.5 = 24/1.5

x² = 16

x = ±4

Substitute x = 4 in (I)

y = 0.5 * 4² - 10

= 0.5*16 - 10

= 8- 10

y = -2

Substitute x = -4 in (I)

y = 0.5 * (-4)² - 10

= 0.5*16 - 10

= 8- 10

y = -2

5 0

3 years ago

The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm2/m

Mnenie [13.5K]

Answer:

The base is reducing at a rate of 3.4cm per min.

Step-by-step explanation:

Let The Height of the Triangle, h

Area of the triangle = A

Area of a Triangle, $A= \frac{1}{2}bh$

When $A=190 cm^2, h=10cm$

$190= \frac{1}{2}*b*10\\b=38cm$

$\frac{dA}{dt}=\frac{1}{2}h\frac{db}{dt}+ \frac{1}{2}b\frac{dh}{dt}\\\frac{dh}{dt}=1 cm/min, \frac{dA}{dt}=2cm^2/min,$

$2=\frac{1}{2}*10*\frac{db}{dt}+ \frac{1}{2}*38*1\\2=5\frac{db}{dt}+19\\2-19=5\frac{db}{dt}\\-17=5\frac{db}{dt}\\\frac{db}{dt}=-\frac{17}{5} =-3.4 cm/min$

The base is reducing at a rate of 3.4cm per min.

8 0

3 years ago