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NNADVOKAT [17]
3 years ago
9

joey made a deposit into an account that earns 6% simple interest.After three years, joey had earned $400. How much was joey's i

nitial deposit
Mathematics
2 answers:
Igoryamba3 years ago
4 0

Answer:

2222.22

Step-by-step explanation

Sergio [31]3 years ago
3 0

Answer:

Step-by-step explanation:

To find the amount deposited, we will simply use the formula for calculating simple interest.

Simple Interest = pxrxt/100     (fraction)

Where p = principal

      R= Rate

           T= Time

Principal is the initial amount deposited which we are ask to find.

R is given to be 6%  and T is the time which is given in years

Simple interest is the interest earned over the year which is given to be $400

Lets substitute our variable into the equation

Simple Interest = pxrxt/100    (fraction)

$400  = P × 6 × 3   /     100

$400 = 18p/100    (fraction)

We will then cross multiply

$40 000  =   18 P

To get  the value of P, we divide both-side of the equation by 18

4000/18 = 18p/18     (fractions)

$2222.22 =  P

P = $2222.22

credits: ummuabdallah

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What is an equation of the line that passes through the points (-5,-1) and (5,3)?
Mademuasel [1]

Answer:

The equation of the line is:

y=\frac{2}{5}x+1

Step-by-step explanation:

Given the points

  • (-5, -1)
  • (5, 3)

Finding the slope between points

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-5,\:-1\right),\:\left(x_2,\:y_2\right)=\left(5,\:3\right)

m=\frac{3-\left(-1\right)}{5-\left(-5\right)}

m=\frac{2}{5}

Using the point-slope form to find the line equation

y-y_1=m\left(x-x_1\right)

substituting the values m = 2/5 and the point (5, 3)

y-3=\frac{2}{5}\left(x-5\right)

Add 3 to both sides

y-3+3=\frac{2}{5}\left(x-5\right)+3

y=\frac{2}{5}x+1

Thus, the equation of the line is:

y=\frac{2}{5}x+1

4 0
3 years ago
−6x + 6y = 6 −6x + 3y = −12
tatuchka [14]

Answer:

x = 0

y = 2

Step-by-step explanation:

−6x + 6y = 6 −6x + 3y = −12

-6x+6x+6y-3y = 6

3y = 6

y = 2

checking:

6-6x+3.2 = -12

6-6x+6 = -12

12-6x = 12

x = 0

checking 2:

since x = 0 we ignore it and its multipliers from the equation:

6y=6+3y = 12

6.2 = 12 (check)

6+3.2 = 12

6+6 = 12 (check)

8 0
3 years ago
The sum of the squares of two numbers is 8 . The product of the two numbers is 4 . Find the numbers.
fenix001 [56]

Hello there.

First, assume the numbers x,~y such that they satisties both affirmations:

  • The sum of the squares of two numbers is 8.
  • The product of the two numbers is 4.

With these informations, we can set the following equations:

\begin{center}\align x^2+y^2=8\\ x\cdot y=4\\\end{center}

Multiply both sides of the second equation by a factor of 2:

2\cdot x\cdot y = 2\cdot 4\\\\\\ 2xy=8~~~~~(2)^{\ast}

Make (1)-(2)^{\ast}

x^2+y^2-2xy=8-8\\\\\\ x^2-2xy+y^2=0

We can rewrite the expression on the left hand side using the binomial expansion in reverse: (a-b)^2=a^2-2ab+b^2, such that:

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The square of a number is equal to 0 if and only if such number is equal to 0, thus:

x-y=0\\\\\\ x=y~~~~~~(3)

Substituting that information from (3) in (2), we get:

x\cdot x = 4\\\\\\ x^2=4

Calculate the square root on both sides of the equation:

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Once again with the information in (3), we have that:

y=\pm~2

The set of solutions of that satisfies both affirmations is:

S=\{(x,~y)\in\mathbb{R}^2~|~(x,~y)=(-2,\,-2),~(2,~2)\}

This is the set we were looking for.

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