Humberto evaluates the expression 4t² for t=3. what is the answer??
1 answer:
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Answer:
The number of red marbles = 152
The number of blue marbles = 228 and
the number of green marbles = 190
Step-by-step explanation:
Let x be the number of red marbles, y be the number of blue marbles and z be the number of green marbles.
It is given that the total marbles = 570.
Therefore, x + y + z = 570 --- (1)
It is also given that the ratio of red to blue marbles is 2 : 3.
Therefore, x : y = 2 : 3
or 3x = 2y --- (2)
It is also given that the ratio of red to green marbles is 4 : 5.
Therefore, x : z = 4 : 5
or 5x = 4z --- (3)
From (2),
From (3),
Substituting the above in (1), we get,
Multiply both sides by 4.
4x + 6x + 5x = 2280
15x = 2280
Divide both sides by 15.
x = 152
Hence,
y =
y = 228
z =
z = 190
Therefore,
The number of red marbles = 152
The number of blue marbles = 228 and
the number of green marbles = 190
<u>Check:</u>
Total number of marbles = 152 + 228 + 190 = 570
Ratio of red to blue marbles = 152 : 228 = 2 : 3
Ratio of red t green marbles = 152 : 190 = 4 : 5
The answer is 
.
Explanation:
In order to subtract the fractions, we must make them like fractions. To do this, the denominators must be the same by multiplying (only). Since the first fraction is
, 3 can be multiplied by 2 to get 6, which is the other fraction, we can multiply it. Whatever you do to the denominator you must do to the numerator. Now multiply 2 by the numerator (10) to get 
. Now we can subtract the fractions and 
to get 13/6. Since this fraction is not in mixed fraction form yet, we must do that first. goes into 13 twice, so the whole number is 2 and there is still 1 left, making the fraction 
. Therefore, the difference is 2 .
Explanation:
In order to subtract the fractions, we must make them like fractions. To do this, the denominators must be the same by multiplying (only). Since the first fraction is