Find the solution set of the system of equations below y=1/2x-1 and x+y=4
1 answer:
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<h2>[A] Plane S contains points B and E.</h2>
False
As indicated in Figure A below, Plane S contains only point B (remarked in red). Point E (remarked in blue) lies on plane R.
<h2>[B] The line containing points A and B lies entirely in plane T.</h2>True
As indicated in Figure B below, the line containing points A and B lies entirely in plane T. That line has been remarked in red and it is obvious that lies on plane T.
<h2>[C] Line v intersects lines x and y at the same point.</h2>False
As indicated in Figure C below, line v intersects lines x and y, but line x in intersected at point B while line y (remarked in red) is intersected at point A (remarked in blue), and they are two different points, not the same.
<h2>[D] Line z intersects plane S at point C.</h2>True
As indicated in Figure D below, line z that has been remarked in yellow, intersects plane S at point C that has been remarked in blue.
<h2>[E] Planes R and T intersect at line y.</h2>True
As indicated in Figure E below, planes R and T intersect at line y. The line of intersection has been remarked in red.
Answer:
2.25
Step-by-step explanation:
Given the cost model:
C(l) = l3 – l2 + l + 2.5
l = Length fo package
The length of a package that cost $11.00
11 = l³ - l² + l + 2.5
From the table given :
Length of mail which cost $11 will just be slightly greater Than 2 as the cost of 2 length mail cost 8.50
Taking l as 2.20
2.2^3 - 2.2^2 + 2.2 + 2.50 = 10.508
Taking a slightly higher value :
Put l = 2.25
2.25^3 - 2.25^2 + 2.25 + 2.50 = 11.078
Ww can conclude that the length of mail would be 2.25
