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3 years ago

1. Stephen works for an environmental protection agency

Mathematics

1 answer:

lord [1]3 years ago

8 0

Answer:

Area to be removed = 3600000 feet³

Step-by-step explanation:

We need to calculate the volume of soil to be removed. We have been already provided with area of the lot in feet.

Total Area of soil = 1200' x 1500'

Where soil to be removed is given in inches, convert it into feet

Soil to be removed = 24''=2'

Multiply both the the value to get the volume of soil to be removed so the soil is not a health hazard

Area to be removed = 1200' x 1500' x 2'

Area to be removed = 3600000 feet³

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kotegsom [21]

Answer:

i think its b

Step-by-step explanation:

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3 years ago

Urgenttttt please I need it fast

dolphi86 [110]

Answer:

Below in bold.

Step-by-step explanation:

c) 3 x (9^2)^3/4 x ((81^3)^5/6

= 3 x 81^3/4 x 81^15/6

= 3 x 81^(3/4 + 15/6)

= 3 x 81^13/4

= 3 x 3^13

= 3^14

= 4,782,969.

f) (5x^-1y^2)^-2 / (25 x^2 y - 1)^2

= 5^-2 x^2y^-4 / 625 x^4y^-2

= 5^-2 x^-2 y^-2 / 5^4

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3 years ago

Help pure people pls

Sedaia [141]

Answer:

Option (B). Perimeter of the quadrilateral ABCD= 14.6 units

Step-by-step explanation:

From the figure attached,

Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).

Length of AB = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

= $\sqrt{(3-1)^2+(5-3)^2}$

= $\sqrt{8}$

= 2.83 units

Length of AD = $\sqrt{(3-5)^2+(5-3)^2}$

= $\sqrt{8}$

= 2.83 units

Length of BC = $\sqrt{(1-3)^2+(3+1)^2}$

= $\sqrt{20}$

= 4.47 units

Length of DC = $\sqrt{(5-3)^2+(3+1)^2}$

= $\sqrt{20}$

= 4.47 units

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7 0

3 years ago

Select the correct answer.

Musya8 [376]

Answer:

Before Tim ate any of the jellybeans, here are numbers:

pineapple or p =10

raspberry or r = 10

orange or o = 10

Tim has eaten 6 orange and 4 pineapple jellybeans. Hence, what's left are:

p = 10-4 =6

o = 10-6 =4

r = 10 so now total jelly beans are 20

So the probability of getting a raspberry is:

p(r) = number of r/total

10/20 or 50%

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3 years ago

Let c be parametrized by x = et sin (10t) and y = et cos (10t) for 0 ≤ t ≤ 2. find the length l of

marysya [2.9K]

$C:x(t)=e^t\sin10t;\,y(t)=e^t\cos10t;\,0\le t\le2$

$\displaystyle\int_0^2\sqrt{x'(t)^2+y'(t)^2}\,\mathrm dt$
$\displaystyle=\int_0^2\sqrt{(e^t\sin10t+10e^t\cos10t)^2+(e^t\cos10t-10e^t\sin10t)^2}\,\mathrm dt$
$\displaystyle=\int_0^2e^t\sqrt{\sin^210t+20\sin10t\cos10t+100\cos^210t+\cos^210t-20\sin10t\cos10t+100\sin^210t}\,\mathrm dt$
$=\displaystyle\int_0^2e^t\sqrt{1+100}\,\mathrm dt$
$=\displaystyle\sqrt{101}(e^2-1)$

7 0

3 years ago