Given:
m∠APD = (7x + 1)°
m∠DPC = 90°
m∠CPB = (9x - 7)°
To find:
The measure of arc ACD.
Solution:
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠APD + m∠DPC + m∠CPB = 180°
7x° + 1° + 90° + 9x° - 7° = 180°
16x° + 84° = 180°
Subtract 84° from both sides.
16x° + 84° - 84° = 180° - 84°
16x° = 96°
Divide by 16° on both sides.
x = 6
m∠APB = 180°
m∠BPD = (9x - 7)° + 90°
= (9(6) - 7)° + 90°
= 47° + 90°
m∠BPD = 137°
m∠APD = m∠APB + m∠BPD
= 180° + 137°
= 317°
<em>The measure of the central angle is congruent to the measure of the intercepted arc.</em>
m(ar ACD) = m∠APD
m(ar ACD) = 317°
The arc measure of ACD is 317°.
Hello from MrBillDoesMath!
Answer:
4/5
Discussion:
80% = => percent means "per 100"
80/100= => 80 = 8 * 10; 100 = 10 * 10
(8*10)/(10*10) = => cancel 10 from numerator and denominator
8/10 = => divide numerator and denominator by 2
4/5
Thank you,
MrB
Reciprocal means the opposite so the reciprocal of 6/5 is 5/6
x = 4 and x = - 9
In both cases the angles inside the parallel lines are same sided interior angles
24x - 1 + 20x + 5 = 180
44x + 4 = 180 (subtract 4 from both sides )
44x = 176 ( divide both sides by 44 )
x = 
= 4
Similarly
x + 109 + x + 89 = 180
2x + 198 = 180 ( subtract 198 from both sides )
2x = - 18
x = 
= - 9
