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Reil [10]
3 years ago
13

Annette has finished 20 of her homework problems. That is 80% of the total assinged by her math teacher. How many pronlems were

assinged?
The possible answers are:
16
25
30
32
Mathematics
1 answer:
horrorfan [7]3 years ago
7 0
So 20=80%' % means out of 100 so 80%=80/100 so 20=80/100 we try to get to 100/100 so 20=80/100 5=20/100 5 times 20=100 so 25=100/100 there were 25 questions total
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What is the measure of the third angle in the similar triangles below?
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65°

Step-by-step explanation:

All triangles equal 180 degrees. So just subtract the other values.

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Use addition to solve the linear system of equations. Include all of your work in your final answer. \(\left\{ \right.\) 3x-y=6
ad-work [718]

Answer:

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

Step-by-step explanation:

We need to solve the linear system of equations.

3x-y=6 \\y=x-4

We can write second equation y=x-4  as: -x+y=-4

Let:

3x-y=6--eq(1)\\ -x+y=-4--eq(2)

Now, Adding equation 1 and 2

3x-y=6\\ -x+y=-4\\--------\\2x+0y=2\\2x=2\\x=\frac{2}{2}\\x=1

So, we get x = 1

Now, put value of x in second equation to find value of y:

y=x-4\\Put\:x=1\\y=1-4\\y=-3

So, we get y = -3

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

4 0
3 years ago
Marie plants flowers in a planter that is 1 1/2 feet long and 1 2/3 feet wide. She plans to cover the entire area with fertilize
Arisa [49]

Answer:

2 3/6

Step-by-step explanation:

You must turn 1 2/3 and 1 1/2 into improper fractions. You then multiply them and get an answer of 15/6, but since 6 can go into 15 twice (6x2=12+3=15), you get a whole of 2 and 3/6.


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3 years ago
I really need help quick
Natali [406]

Answer:

\sf x=2+\sqrt{6},\:x=2-\sqrt{6}

Explanation:

\sf y = x^2 -4x

given that y = 2

\sf x^2 -4x = 2

\sf x^2 -4x -2 = 0

using quadratic formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \    \ \ when  \   ax^2 + bx + c = 0

\rightarrow \sf x_{1,\:2}=\dfrac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}

\rightarrow \sf x_1=\dfrac{-\left(-4\right)+2\sqrt{6}}{2\cdot \:1},\:x_2=\dfrac{-\left(-4\right)-2\sqrt{6}}{2\cdot \:1}

\rightarrow \sf x=2+\sqrt{6},\:x=2-\sqrt{6}

in decimals:

\rightarrow \sf x=4.45 , \ -0.45

5 0
2 years ago
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