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3 years ago

Identify the percent of change as an increase or a decrease. 9 points to 4 points

Mathematics

1 answer:

padilas [110]3 years ago

8 0

Answer:

55.55% decrease

Step-by-step explanation:

$change\% = \frac{final \: point \: - initial \: point}{initial \: point \: value} \times 100$

In the question ,

Initial point value = 9

Final point value = 4

Change% = $\frac{4 - 9}{9} \times 100 = \frac{ - 5}{9} \times 100 = - 55.55\%$

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Would anyone be willing to helppp? I’ll be giving brainliest when I get the chance too

anyanavicka [17]

Step-by-step explanation:

1. add the numbers all together

(of the pets)

= 40 pets total

40 pets =100%

1 pet = 2.5%

percents:

Cat= 10, or 25%

Dog = 15, or 37.5 %

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bird= 7 or 17.5%

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5 0

3 years ago

Find the slope of the line that passes through (7,2) and (3,3)

Sav [38]

Answer:

1 over 4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the multiplicative inverse of 6 + 2i

Marina CMI [18]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2774989

________________

Find the multiplicative inverse of

$\mathsf{z=6+2i}$

________

The inverse multiplicative of $\mathsf{z=a+bi}$ is

$\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\qquad\quad(a\ne 0~~and~~b\ne 0)}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\cdot \dfrac{a-bi}{a-bi}}\\\\\\
=\mathsf{\dfrac{1\cdot (a-bi)}{(a+bi)\cdot (a-bi)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-\,\diagup\hspace{-10}abi+\,\diagup\hspace{-10}abi-(bi)^2}}$

$=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot i^2}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot (-1)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2+b^2}}\\\\\\\\
\therefore~~\mathsf{\dfrac{1}{a+bi}=\dfrac{a}{a^2+b^2}-\dfrac{b}{a^2+b^2}\,i\qquad\quad\checkmark}$

________

For this question,

$\mathsf{z=6+2i}$

So,

$\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{6+2i}}\\\\\\
=\mathsf{\dfrac{6}{6^2+2^2}-\dfrac{2}{6^2+2^2}\,i}\\\\\\
=\mathsf{\dfrac{6}{36+4}-\dfrac{2}{36+4}\,i}\\\\\\
=\mathsf{\dfrac{6}{40}-\dfrac{2}{40}\,i}$

$\therefore~~\mathsf{\dfrac{1}{z}=\dfrac{3}{20}-\dfrac{1}{20}\,i}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

6 0

3 years ago

Read 2 more answers

1. slope == 5, through (3, 13)

GuDViN [60]

I’m assuming you’re trying to find the equation of a line that intersects the point. In order to do this you need to plug in your points into the equation that at the moment just has your slope.

y=5x —> 13=5(3)+b —> 13=15+b —> 13-15=b

—> b=-2

Now that you finally found your b (y-intercept) you can just plug it in!

y=5x-2

8 0

3 years ago

Which of the following is an example of a valid use of the multiplication property of equality? A. to isolate s in the equation

marusya05 [52]

Answer:

D. to isolate s in the equation –4s = –12, multiply both sides of the equation by -1.

Step-by-step explanation:

We have a set of an example of equations; we need to study the use of multiplication property of equality.

A. to isolate s in the equation s – 4 = –12, divide both sides of the equation by.In this sentence, to isolate s we do not need multiplication only addition and subtraction.

B. to isolate s in the equation s – 4 = –12, multiply both sides of the equation by. In this sentence, to isolate s we do not need multiplication only addition and subtraction.

C. to isolate s in the equation –4s = –12, divide both sides of the equation by -4. This sentence is correct, and it uses division. However, we are studying multiplication property not division.

D. to isolate s in the equation –4s = –12, multiply both sides of the equation by -1. Firstly, it is a good idea to change both negative signs to positive by multiplying by -1 to isolate s.

Finally, we can conclude that a valid use of the multiplication property of equality is D. to isolate s in the equation –4s = –12, multiply both sides of the equation by -1.

5 0

4 years ago