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weeeeeb [17]
3 years ago
15

Which of the following options correctly represent a formula with Absolute References?

Computers and Technology
2 answers:
ludmilkaskok [199]3 years ago
4 0

Answer:

D.)=($A$1-$B$1)

Explanation:

The $ sign placed in between the characters of a cell makes the cell an absolute reference in any formula that involves the cell.

For example, the function "=A1 - $B$2" would give a result equivalent to "=A1 - B2" however, a drag down of the formula would result in a change of the function A1 to A2, A3, A4, A5...

Hence from the options, =($A$1-$B$1) is the only formula with absolute references.

lakkis [162]3 years ago
3 0
The answer is D =(<span>$A$1-$B$1) 

sources:just took the test</span>
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Write a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters.
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Answer:

Explanation:

The python code for the question is attached in the image below.

The objective here is to write a code in python with a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters. Otherwise, it should return False.

SEE BELOW FOR THE CODE.

alphabet = "abcdefghijklmnopqrstuvwxyz"

test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]

test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]

def histogram(s):

   d = dict()

   for c in s:

       if c not in d:

           d[c]=1

       else:

           d[c] += 1

   return d

def has_duplicates():

   for string in test_dups:

       dictionary=histogram(string)

       duplicates=False

       for ch in dictionary.keys():

           if dictionary[ch] > 1:

               duplicates=True

               break

       if duplicates==True:

           print(string,"has duplicates")

       else:

           print(string,"has no duplicates")

def missing_letters(string):

   answer=""

   for ch in alphabet:

       if ch not in string:

           answer=answer+ch

   return answer

print("__________________________________________")

print(" Calling has_duplicates() function")

print("__________________________________________")

has_duplicates()

print("\n______________________________________________")

print("Calling missing_letters() function in for loop")

print("______________________________________________")

for i in test_miss:

   answer=missing_letters(i)

   if len(answer)>=1:

       print(i,"is missing letters",answer)

   else:

       print(i,"uses all the letters")

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3 years ago
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