Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
baki baki ni ore nani wo kokoro wo da yo kunagona no kudake nani wo?
Answer:
Any equation of the line with slope 2/3.
Parallel lines have identical slope.
Step-by-step explanation:
3y - 2x = - 24
3y = 2x - 24
y = 2/3x - 8
186,648 hits (which in baseball is pretty much impossible lol)
Answer:
0
Step-by-step explanation:
Slope = y2- y1/x2 - x1
Given
x1 = 6
y1 = -3
x2 = -4
y2 = -3
Slope = -3 -(-3) /-4 - 6
= -3 + 3 /-10
= 0/10
= 0
This means that the line of the slope is horizontal
