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2 years ago

PLZ HELP ME!! if F(x) = x - 7 and G(x) = x, what is G(FX))?

Mathematics

2 answers:

Aleonysh [2.5K]2 years ago

3 0

Answer:

alright so this doesn't make any sense so

Step-by-step explanation:

i can't really help but 12 is the answer

kap26 [50]2 years ago

3 0

Answer:

G(F(x)) = x-7

Step-by-step explanation:

G(F(x)) is composition of functions that means to plug in F(X) into G function.The new variable will be F(X) instead of X.

G(x) = x, F(x) = x - 7

G(F(x)) = x-7

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Write 15 + 45 as a product of two factors using the gcf and the distributive property.

Alja [10]

Answer:

15 (3+1)

Step-by-step explanation:

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2 years ago

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The ball's height (in meters above the ground), xxx seconds after Antoine threw it, is modeled by: h(x)=-2x^2+4x+16 How many sec

zlopas [31]

Answer:

Step-by-step explanation:

If we are given the quadratic model, we know that the height of anything on the ground is 0 meters, so that model becomes

$0=-2t^2+4t+16$ I changed your x's to t's since t is for time.

Now we need to factor that quadratic and solve for time:

$0=-2(t^2-2t-8)$

Since -2 definitely does not equal 0, then

$t^2-2t-8=0$

Factor that and find t values of 4 and -2. Again, we know that time will never be negative, so

t = 4 seconds.

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3 years ago

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A marketing company is designing a new package for a box of cereal. They have determined that the function C(x) = 4.5 x2 models

Vlad1618 [11]

So the function is

$\\ \rm\rightarrowtail y=4.5x^2$

As we know

x²≥0
x≥0

hence domain is

$\\ \rm\rightarrowtail D_f\in R$

Least value of function is at x²=0 i.e 0

Hence range:-

$\\ \rm\rightarrowtail R_f\in [0,\infty)$

6 0

2 years ago

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago

I’m having a lot of trouble, can someone guide me, step by step?

shutvik [7]

Answer:

Hi hopefully this helps you!

Step-by-step explanation:

To find the area of a circle you can use the formula A = πr^2

The radius of a circle is just the diameter divided by 2. In this case we know the diameter is 3, so the radius is 1.5

A = π(1.5)^2

= 7.07

Because this is a semicircle, divide this area by 2

= 3.53429 in^2

Add up the area of this semi circle with the area of the rectangle

A = (3.53429) + (3x4)

= 15.53429 in^2

To find the circumference/ perimeter of a circle use this formula C = 2πR

C = 2π(1.5)

= 9.42478 inches

Again because this is a semicircle, divide by 2

= 9.42478 / 2

= 4.71239 inches

To find the perimeter of this entire shape add up the circumference of the semicircle and the rectangle's sides and bottom

P = 4.71239 + 4 + 4 + 3

= 15.71239 inches

So the final answer would be

A = 15.53 squared inches

P = 15.71 inches

Hope this helps! Best of luck in your studies <3

6 0

2 years ago