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velikii [3]
3 years ago
14

Consider this claim: Changes in environmental conditions always result in new ecosystems and loss of biodiversity characterized

by an increase in the number of some species, the evolution of new species, and the extinction of some species.
Use what you have learned from the lesson, as well as reliable and reputable resources, to evaluate this claim. Use at least three examples from the lesson and other sources to support the valid ideas in the claim and refute the invalid ones. Add a list of your resources at the end of your response. Then, draw a conclusion about the stability of ecosystems, how and what can affect the stability of ecosystems, and how changes in the environment may affect the types and number of living things in an ecosystem.
Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

If a desert became flooded, some species would immeadiately go extinct, distrupting the ecosystem, biodiversity, and the food web. This flood might cause new species to enter the ecosystem as well, through means such as rafting. Other species would be forced to adapt to the new environment, leading to adaptation and possibly speciation. For a time the ecosystem would not be very stable, but after a relatively short time, 10 or 20 years, the ecosystem could stabilize itself. So my conclusion is that ecosystems are relatively fluid, they can adapt to almost anything if they have enough time and the change in environment isn’t too drastic.

Step-by-step explanation:

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A spinner numbered 1 through 12 is spun. Find the probability that
anastassius [24]

Answer:

\dfrac{1}{6}

Step-by-step explanation:

Let <em>A</em> be the event of getting an odd number.

<em>P(A)</em> be the probability of getting an odd number.

Total odd numbers here are 6 i.e. \{1,3,5,7,9,11\}

Here, total numbers in the game are 12 i.e \{1,2,3,....,12\}.

Formula for probability of an <em>event E</em> can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A) = \dfrac{6}{12}\\\Rightarrow \dfrac{1}{2}

Let <em>B</em> be the event of getting 11.

<em>P(B)</em> be the probability of getting 11.

Total number of possible cases is 1.

P(B) = \dfrac{1}{12}

P(A \cap B) is the probability that we get 11 and an odd number.

Possible number of cases = 1

P(A\cap B) = \dfrac{1}{12}

<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.

P(B/A) = \dfrac{P(A \cap B)}{P(A)}\\\Rightarrow \dfrac{\dfrac{1}{12}}{\dfrac{1}{2}}\\\Rightarrow \dfrac{1}{6}

Hence, P(B/A) = \dfrac{1}{6}

4 0
3 years ago
Read 2 more answers
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