Answer- A- 20, B-70, c-20, d-50, e- 110
I think
Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
59%
Step-by-step explanation:
There are 7 days out of 14 that are 20 or more
That would be 59%
Answer:
The inverse of
y
=
2
x
is
y
=
log
2
x
Explanation:
This is how to do it.
From the given
y
=
2
x
interchange the variables so that
x
=
2
y
then solve for y:
x
=
2
y
take the logarithm of both sides with base
=
2
log
2
x
=
log
2
2
y
log
2
x
=
y
and
y
=
log
2
x
The graph of
y
=
2
x
and its inverse
y
=
log
2
x
. They are symmetric with the line
y
=
x
graph{(y-2^x)(y-log x/log 2)(y-x)=0[-20,20,-10,10]}
