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3 years ago

I don’t understand what #5 is asking me to do! Ty

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

4 0

You have to explain how you knew to use 55 and 120, not another option.

Hope it helped! :)

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If g = 1/5 how much is 15 g

dexar [7]

The answer to this question is 3. to solve this, multiple g, which is 1/5, by 15. This will give you 15/5. now, divide 15 by 5 and you will get 3. I hope this helps!

5 0

3 years ago

Read 2 more answers

The safe load for a certain horizontal beam used to hold up part of a building varies inversely as the length between the

Misha Larkins [42]

The statement is true.

Answer: Option 1.

<u>Explanation:</u>

An horizontal beam is constantly flat and has a consistent cross-segment. Notwithstanding normal shaft parameters, bar has the accompanying properties: Direction. A flat shaft might be situated either along the worldwide X-hub or worldwide Y-pivot.

A horizontal beam is used to hold a building up right and to give the support to the building. But the length of the horizontal beam differs in an inverse way between the supports.

6 0

3 years ago

Find P on AB that is 2/3 of the distance from A(-3,-5) to B(9,4).

Ludmilka [50]

A line segment can be divided into ratios.

<em>The coordinate of P on line segment AB is (5,1)</em>

Given

$A = (-3,-5)$

$B = (9,4)$

The position of P from A to B is:

$P_A = \frac 23$

So, from P to B would be:

$P_B =1 - \frac 23$

$P_B = \frac 13$

So, the ratio is:

$m : n = \frac 23 : \frac 13$

Simplify

$m : n = 2 :1$

<u>The coordinate of point P is:</u>

$P = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

So, we have:

$P = (\frac{2 \times 9 + 1 \times -3}{2 + 1},\frac{2 \times 4 + 1 \times -5}{2 + 1})$

$P = (\frac{15}{3},\frac{3}{3})$

$P = (5,1)$

<em>Hence, the coordinate of P is (5,1)</em>

Read more about line ratios at:

brainly.com/question/8847082

8 0

3 years ago

Mateo teaches a continuing education class at the library on tuesday nights. he estimates that 75% of his students are satisfied

vredina [299]

The computed value must closely match the real value for a model to be considered valid. If the percentage of pleased or very satisfied students remains close to 75% after Mateo surveys additional students, Mateo's model is still viable. The model is faulty if the opposite is true.

<h3>How will mateo know whether his model is valid or not?</h3>

In general, a valid model is one whose estimated value is close to the real value. This kind of model is considered to be accurate. It must be somewhat near to the real value if it doesn't resemble the real value.

If the findings of the survey are sufficiently similar to one another, then the model may be considered valid.

P1 equals 75%, which is the real assessment of the number of happy pupils

P2 is 70 percent; this represents the second assessment of happy pupils

In conclusion, The estimated value of a model has to be somewhat close to the real value for the model to be considered valid. If the number of students who are either pleased or extremely satisfied remains close to 75 percent following Mateo's survey of more students, then Mateo's model is likely accurate. In any other scenario, the model cannot be trusted.