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Mashutka [201]
3 years ago
5

Can sin(x)* cos(x) +{sin(x)*cos(x)+cos(x)*sin(x)} be simplified? If so, please simplfy it and show your work.

Mathematics
1 answer:
Art [367]3 years ago
6 0

Answer:

Yes that is just 3*cos(x)*sin(x)

Step-by-step explanation:

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What is the radius of a sphere that has a surface area of 951.1 in2?
dusya [7]

Answer:

FORMULA FOR SURFACE AREA OF SPHERE = 4 pi r^2  

r = 6 " area = 4 pi X 6 X 6 = 144 pi " squared  

r = 12 "  

area = 4 X pi X 12 X 12 = 576 pi" squared  

ANSWER Area will be 4 times the original

Step-by-step explanation:

4 0
3 years ago
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the parking lot has five rows there are 10 parking spaces in the truck how many parking spaces are in the lot
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There are 50 parking spaces because 10×5=50
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Which integer in the set has the smallest value (-17, -7, -12, 2)? A. 2 B. -7 C. -12 D. -17
swat32

Answer:

Step-by-step explanation:

2. 3/2 = 1.5. 3. 7. 5. 7/5 = 1.4. 4. 17. 12. 17/12 = 1.416666 ... l.3(d). Leta be the least upper bound (i.e., the smallest number at least as great as.

3 0
3 years ago
What is the solution to this equation 4x + 2 ( x + 6 ) = 36
Margaret [11]

The answer is A. x=4.


Start off by distributing the parentheses into the equation.

4x+2(x+6)=36

4x+2x+12=26


Combine like terms.

4x+2x=6x

6x+12=36


Now solve the equation as normal. Begin by subtracting 12 from both sides to isolate the variable.

6x+12=36

-12 -12

---------------

6x = 24


Divide 6 on both sides to find x.

6x=24

---- -----

6 6

x=4


The solution to the equation is 4.

4 0
3 years ago
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The Edward James Toy Company uses a Kanban system to make plastic wheels that are a component of several toys. The waiting time
pickupchik [31]

Answer:

N_c \approx 5.0

Step-by-step explanation:

From the question we are told that:

Waiting time for a container of the wheels during production T_w=0.25day

Average processing time is T_a=0.15 day per container

Wheel per container N_w=200

Total wheel per day D=2000

Policy variable of X=5%  

Generally the equation for Total number of container N_c is mathematically given by

N_c=DT(\frac{1+X}{N_w} )

Where

Total time T=T_w+T_a

T=0.15+0.25

Therefore

N_c=DT(\frac{1+X}{N_w} )

N_c=2000*0.40(\frac{1+0.5}{200} )

N_c=(\frac{840}{200} )

N_c=4.2

N_c \approx 5.0

Therefore the number of Kanban containers needed for the wheels is

N_c \approx 5.0

3 0
3 years ago
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