Answer:
24= 2*2*2*3= 2^3*3
Step-by-step explanation:
Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
Answer:
use the slope equation (y2-y1) / (x2 -x1). plug in values and solve
(-1 -7) / (9 -(-3)) (subtracting a negative is the same as adding a positive)
-8 / 12 (simplify)
m = -2/3
then, plug in one of the points and the slope into the slope-point equation.
(y - y1) = m (x - x1) (the point-slope form)
y - 7 = -2/3( x - (-3)) (plug in the slope and point 1 values, then solve)
y - 7 = -2/3x - 2 (add 7 to both sides)
y = 2/3x +5 (the answer)
Step-by-step explanation:
I hope this helps :))
You would shade in 135 of the squares in the grid(s)
